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raketka [301]
4 years ago
11

Can someone plssss answer these I’m so confused I’m begging u I’l love u foreve

Mathematics
1 answer:
madam [21]4 years ago
7 0

Answer:

22) RT ; angles 2 and 4 are alternate interior angles

23) RT ; angles 1 and 3 are alternate interior angles

24) TV; same-side interior angles (some classes called them consecutive interior angles)

25) RV; same-side interior angles (some classes call them consecutive interior angles)

Step-by-step explanation:

The transversal is the a "line" going through at least 2 others helping to form the angles in question.

22) The line segment going through two line segments that contain angles 2 and 4 is:

RT.

Angles 2 and 4 are alternate interior angles because they happen inside the parallel lines on opposite sides of the transversal at the different intersections of RT and the parallel lines it goes through.

23) The line segment going through at least two line segments that contain angles 1 and 3 is:

RT.

Angles 1 and 3 are alternate interior angles because they happen inside the parallel lines on opposite sides of the transversal at the different intersections of RT and the parallel lines it goes through.

The cool thing about 24 and 25 is that they give you the transversal in the name of the angle.

24) Angles TVR and VTS are being formed by the line segment TV and the parallel line segments that it intersects.  TV is the transversal.

Angles TVR and VTS are same side interior angles because they happen inside the parallel lines on the same side of the transerval at the different intersections of TV and the parallel lines it goes through.

25) Angles SRV and RVT are being formed by the line segment RV and the parallel line segments that it intersects.  RV is the transversal.

Angles SRV and RVT are same side interior angles because they happen inside the parallel lines on the same side of the transerval at the different intersections of RV and the parallel lines it goes through.

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antiseptic1488 [7]
The answer would be B.About 25 inches! :)
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3 years ago
HELP ME I HAVE ONLY TODAY LEF TFOR SCHOOL PLS!!!!!
sesenic [268]

Answer:

B

Step-by-step explanation:

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6 0
3 years ago
The height h (in feet) of an object dropped from a ledge after x seconds can be modeled by h(x)=−16x2+36 . The object is dropped
kakasveta [241]

Check the picture below.

\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(t) = -16t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&\\ \qquad \textit{at "t" seconds} \end{cases}

so the object hits the ground when h(x) = 0, hmmm how long did it take to hit the ground the first time anyway?

\bf h(x)=-16x^2+36\implies \stackrel{h(x)}{0}=-16x^2+36\implies 16x^2=36 \\\\\\ x^2=\cfrac{36}{16}\implies x^2 = \cfrac{9}{4}\implies x=\sqrt{\cfrac{9}{4}}\implies x=\cfrac{\sqrt{9}}{\sqrt{4}}\implies x = \cfrac{3}{2}~~\textit{seconds}

now, we know the 2nd time around it hit the ground, h(x) = 0, but it took less time, it took 0.5 or 1/2 second less, well, the first time it took 3/2, if we subtract 1/2 from it, we get 3/2 - 1/2  = 2/2 = 1, so it took only 1 second this time then, meaning x = 1.

\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(x) = -16x^2+v_ox+h_o \quad \begin{cases} v_o=\textit{initial velocity}&0\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&0\\ \qquad \textit{at "t" seconds}\\ x=\textit{seconds}&1 \end{cases} \\\\\\ 0=-16(1)^2+0x+h_o\implies 0=-16+h_o\implies 16=h_o \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x) = -16x^2+16~\hfill

quick info:

in case you're wondering what's that pesky -16x² doing there, is gravity's pull in ft/s².

4 0
3 years ago
What is the answer for <br> -6n-2n=16
djverab [1.8K]

Answer:

n=-2

Step-by-step explanation:

-6n-2n=16

-8n=16

n=16/-8

n=-2

8 0
4 years ago
Read 2 more answers
Find the equation of this line.
Juliette [100K]

Answer:

y = 1/3 x + 2

Step-by-step explanation:

We see points (-3, 1) and (3, 3).

We also see point (0, 2), the y-intercept.

To go from (-3, 1) to (3, 3), go up 2 and right 6.

slope = m = rise/run = 2/6 = 1/3

y = mx + b

y = 1/3 x + 2

6 0
3 years ago
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