Hi, the answer is ;
Answer:
12 dimes and 27 nickels
Step-by-step explanation:
.05N + .1d = 2.55
N= 3d - 9
0.05 (3d-9) + 0.1d = 2.55
0.15d - 0.45 + 0.1d = 2.55
0.25d = 2.55 + 0.45
0.25d = 3
D = 12
N = 3 (12) - 9
N = 36 - 9
N = 27
Answer:
Step-by-step explanation:
24y = 7
Our primary objective here is to get y on it's own side, without any numbers attached.
Since a 24 is attached to the y, we have to divide the 24y by 24.
Remember that whatever we do to one side, we MUST do to the other.
Since 
can't be simplified, that would be our answer.
Please let me know if you need help with anything else. :)
Short answer
For 6: 72 ft^2
For 7: 650 m^2
Six
The base is a square. It's measurement is s = 4
Base = 4^2
Base = 16 ft^2
One triangle
A = 1/2 * b * h
A = 1/2 * 4 * 7
A = 14 tt^2
Four triangles
A = 4 * 14
A = 56 ft^2
Total Area = 56 + 16 = 72 ft^2
Answer 72 square feet
Seven
Triangles
Area of 1 triangle = 1/2 * 10 * 13
Area of 1 triangle = 65
Area of 6 triangles
Area of 6 triangles = 6 * area of 1 triangle
Area of 6 triangles = 390
Base
As near as I can tell, the base is a hexagon. It's using a rather out of the way method of drawing it. I will assume it is a regular hexagon. The area of a regular hexagon is 3 sqrt(3)/2 * S^2 where s is the side of the hexagon.
Area = 3sqrt(3)/2 s^2
s = 10
Area = 3sqrt(3)/2 10^2
Area = 5.1962 * 100 /2
Area = 259.81
Total area
Total area = area of the base + area of the triangles
Total area = 259.81 + 390
Total area (rounded ) = 650
Answer C <<<< answer
I'll do one more in this batch and then you'll need to repost again.
Eight
If you draw two diagonals on the base of the figure, the intersection point will meet the base of the height. Read that a couple of times.
Join the intersection to the midpoint of the length of the square bottom. You should get 3.5
x is found by using the pythagorean theorem.
h = 6
s = 3.5
x = ????
x^2 = 6^2 + 3.5^2
x^2 = 36 + 12.25
x^2 = 48.25
x = sqrt(48.25)
x = 6.95
C <<<< answer
Spinal Cord
hope this helps
Answer:
what does the picture say?
Step-by-step explanation:
