Answer:
A. .
Step-by-step explanation:
We have been given an inequality . We are asked to solve the given inequality for x.
Using distributive property, we will get:
Subtract 2 from both sides:
Divide both sides by 7:
Therefore, option A is the correct choice.
Complete question:
He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is
a) less than 8 minutes
b) between 8 and 9 minutes
c) less than 7.5 minutes
Answer:
a) 0.0708
b) 0.9291
c) 0.0000
Step-by-step explanation:
Given:
n = 47
u = 8.3 mins
s.d = 1.4 mins
a) Less than 8 minutes:
P(X' < 8) = P(Z< - 1.47)
Using the normal distribution table:
NORMSDIST(-1.47)
= 0.0708
b) between 8 and 9 minutes:
P(8< X' <9) =
= P(-1.47 <Z< 6.366)
= P( Z< 6.366) - P(Z< -1.47)
Using normal distribution table,
0.9999 - 0.0708
= 0.9291
c) Less than 7.5 minutes:
P(X'<7.5) =
P(X' < 7.5) = P(Z< -3.92)
NORMSDIST (-3.92)
= 0.0000
Answer:
The equipment elevator is positioned 481 feet closer and the miner equipment is positioned 342 feet closer relative to the surface. The equipment elevator is deeper.
Step-by-step explanation:
The rate that both elevators descend are the same according to the information given in the question.
After 18 seconds, the equipment elevator has descended 18 x 13 = 234 feet.
After another 19 seconds, the equipment elevator has descended for a total of 37 seconds which results in 481 feet and the miner elevator has descended for 19 seconds which gives us a descend of 342 feet.
So they are 481 and 342 feet closer relative to the surface and the equipment elevator is deeper since it has descended for a longer period of time.
I hope this answer helps.
Answer:39 1/5
Step-by-step explanation: