C because if it was constant then for day 3 the distance would be 65.4 instead of 64.8
By doing by over 2 it will equal yeah
Answer:
9 and 11
Step-by-step explanation:
So let's say that the first integer is x.
That means that the second integer is x+2, since it us the next odd number.
This problem can be easily solved with our mind the answer is 9 and 11, but I'll show you the steps to slove this.
We make an equation using these two numbers:
Now all we gotta do is solve for x:
Now we use either splitting the middle term or quadratic formula:
Now we split each terma and solve for x:
Now the question states <em>positive </em>so we can rule out x = -11.
Now we have the first integer x = 9,
the second integer is x+2 = 9+2 =11
So the two consecutive positive odd integers are 9 and 11
Answer:
Step-by-step explanation:
f(x) = x^2 + 4x + 4
f(x + a) = (x + a)^2 + 4(x + a) + 4
f(x + a) = x^2 + 2ax + a^2 + 4x + 4a + 4 Now combine like terms and use the distributive property.
f(x + a) = x^2 + (2a + 4)x + a^2 + 4a + 4
We are told that f(x + a) = x^2 - 6x + 9
So that means that
2a + 4 = - 6 Subtract 4 from both sides.
2a = - 6 - 4
2a = - 10 Divide by 2
a = - 10/2
a = - 5.
But you are not finished. You have to check the last part.
a^2 + 4x + 4 = 9
(a + 2)^2 = 9
Take the square root of both sides
sqrt(a+ 2)^2 = +/- 3
a+2 = 3
a = 1.
Does this work or is it extraneous? It is extraneous because it will not work for 2(a) + 4 = - 6
You get 6 = - 6 which is not correct. But you did give the second best answer.
a + 2 = - 3
a = - 3 - 2
a = - 5 which agrees with your previous answer.
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This is an extremely hard or tricky or sneaky problem. It takes a lot of conniving to get the right answer and 1 is not a left field answer. It just does not happen to be correct.
Answer:
inscribed
Step-by-step explanation:
For any given triangle, the circle inside of it is called the Inscribed circle
