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GarryVolchara [31]
3 years ago
15

What is the volume and surface area of the figure below?

Mathematics
1 answer:
Artist 52 [7]3 years ago
3 0

Answer:

51.8125 yd (not rounded)

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What are the solutions to 3n-1>8 or 4n+3 < -1? *​
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Answer:

3’d

Step-by-step explanation:

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3 years ago
Could someone please help\/brainliest
Sonja [21]
The last statement : Line segments E'F' and G'H' do not intersect and are the same distance apart as EF and GH, is the correct answer. A translation is simply a transformation in which all the point of a figure move the same distance in the same direction. So the points will not intersect.
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What eigen value for this matix <br> (1 -2)<br> (-2 0)
natali 33 [55]

You find the eigenvalues of a matrix A by following these steps:

  1. Compute the matrix A' = A-\lambda I, where I is the identity matrix (1s on the diagonal, 0s elsewhere)
  2. Compute the determinant of A'
  3. Set the determinant of A' equal to zero and solve for lambda.

So, in this case, we have

A = \left[\begin{array}{cc}1&-2\\-2&0\end{array}\right] \implies A'=\left[\begin{array}{cc}1&-2\\-2&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right]=\left[\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right]

The determinant of this matrix is

\left|\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right| = -\lambda(1-\lambda)-(-2)(-2) = \lambda^2-\lambda-4

Finally, we have

\lambda^2-\lambda-4=0 \iff \lambda = \dfrac{1\pm\sqrt{17}}{2}

So, the two eigenvalues are

\lambda_1 = \dfrac{1+\sqrt{17}}{2},\quad \lambda_2 = \dfrac{1-\sqrt{17}}{2}

5 0
2 years ago
Read 2 more answers
Help ASAP please!!!!!!!
Bumek [7]
I think the answer will be (-4,3)
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Simplify the expression. 10P8
GarryVolchara [31]
Ur answer is A but am really beginning sure
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