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Dimas [21]
3 years ago
14

__________ Refers to the difference between the original analog data and the approximation of that data using the techniques for

translating from analog data to digital signals.
A. Quantizing error
B. Handshaking phase
C. Modulating frequency
D. POTS anomaly
E. Amplitude Trellis effect
Computers and Technology
1 answer:
otez555 [7]3 years ago
8 0

Answer:

Quantizing error

Explanation:

In digitisation of analog signal refers to the rounding off of values which are approximately equal to the analog signals. The method of sampling chooses a few point on the analog signal and then these points are joined to round off the value to a near stabilised value. such process is known as Quantization. For any system, during its functioning, there is always a difference in the values of its input and output. The processing of the system results in an error, which is the difference of those values.

The difference between an input value and its quantized value is called a Quantization Error. A Quantizer is a logarithmic function that performs Quantization rounding off the value. An analog-to-digital converter (ADC) works as a quantizer.

You might be interested in
A 'array palindrome' is an array which, when its elements are reversed, remains the same (i.e., the elements of the array are sa
tia_tia [17]

Answer:

Here is the JAVA program:

class Main {    

static boolean isPalindrome(int array[], int starting, int ending) {  /*a boolean method that takes an integer-valued array, and a pair of integers representing the starting and ending indexes of the portion of the array to be tested for being a palindrome */

   if (starting >= ending) {  //base case

       return true;     }  //returns true

   if (array[starting] == array[ending]) {  //recursive case

       return isPalindrome(array, starting + 1, ending - 1);     }  //calls isPalindrome recursively to find out palindrome

   else {  

       return false;    }  }  //returns false if array is not palindrome

 

   public static void main (String[] args) {  //start of main function

   int array[] = { 1,2,3,2,1};  //creates an array

   int size = array.length;   //computes the size of array

 System.out.print(isPalindrome(array, 0, size - 1));    } } //calls method to test array for being  a palindrome

Explanation:

The program works as follows:

array = { 1,2,3,2,1}

starting = 0

ending = size-1 = 5-1 = 4

if (starting >= ending) condition evaluates to false because starting i.e. 0 is not greater or equal to ending i.e. 4. So the program moves to the next if part

if (array[starting] == array[ending])

This becomes:

if (array[0] == array[4])

The element at 0th index is the first element of the array i.e. 1 and the element at 4th index of array is the last element of array i.e. 1. So both these elements are equal so the following statement executes:

return isPalindrome(array, starting + 1, ending - 1);

Now the starting and ending become:

starting+1 = 0+1 = 1

ending-1 = 3

if (starting >= ending) base condition evaluates to false because starting  is not greater or equal to ending. So the program moves to the next if part

if (array[starting] == array[ending])

This becomes:

if (array[1] == array[3])

The element at 1st index is 2 and the element at 3rd index of array is 2. So both these elements are equal so the following statement executes:

return isPalindrome(array, starting + 1, ending - 1);

Now the starting and ending become:

starting+1 = 1+1 = 2

ending-1 = 2

if (starting >= ending) base condition evaluates to true because starting  is  equal to ending. So the following statement executes:

       return true;    

This means the function returns true and this shows that array is a palindrome.

The screenshot of the program and its output is attached.

8 0
3 years ago
Jill is configuring the AutoArchive feature in Outlook 2016. What is the default setting in relation to when AutoArchive
r-ruslan [8.4K]
<h2>Answer:</h2>

(b) 14 days

<h2>Explanation:</h2>

In the presence of thousands of mails each day or week, controlling what items to keep in an archive for cleaning up purposes becomes important. To do this, Outlook comes with an option called AutoArchive. The default setting in relation to when AutoArchive will run is 14 days. To change this setting, user will need to do the following:

i. Navigate to File  > Options > Advanced

ii. Under the AutoArchive menu, click on the AutoArchive settings

iii. Change the settings however way they want.

5 0
3 years ago
A drowsy cat spots a flowerpot that sails first up and then down past an open window. The pot is in view for a total of 0.50 sec
GaryK [48]

Answer:

2.342m

Explanation:

Given

Time = 0.5 s

Height of Window = 2m

Because the pot was in view for a total of 0.5 seconds, we can assume that it took the cat 0.25 seconds to go from the bottom of the window to the top

Using this equation of motion

S = ut - ½gt²

Where s = 2

u = initial velocity = ?

t = 0.25

g = 9.8

So, we have.

2 = u * 0.25 - ½ * 9.8 * 0.25²

2 = 0.25u - 0.30625

2 + 0.30625 = 0.25u

2.30625 = 0.25u

u = 2.30625/0.25

u = 9.225 m/s ------------ the speed at the bottom of the pot

Using

v² = u² + 2gs to calculate the height above the window

Where v = final velocity = 0

u = 9.225

g = 9.8

S = height above the window

So, we have

0² = 9.225² - 2 * 9.8 * s

0 = 85.100625 - 19.6s

-85.100625 = -19.6s

S = -85.100625/19.6

S = 4.342

If 4.342m is the height above the window and the window is 2m high

Then 4.342 - 2 is the distance above the window

4.342 - 2 = 2.342m

6 0
3 years ago
Which option can be used to access more settings than are available in the Backstage view?
Bumek [7]

Answer:

orientation settings

Explanation:

so u can now more about whta u doing

6 0
2 years ago
1110011*110011 binary multiplication
Ganezh [65]

122113420121

Explanation:

8 0
3 years ago
Read 2 more answers
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