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NNADVOKAT [17]
3 years ago
12

Can someone help me I’m stuck on how to do this

Mathematics
1 answer:
Aleksandr [31]3 years ago
7 0

Answer:

Step-by-step explanation:

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Write the set of points from −6−6 to 33 but excluding −2−2 and 33 as a union of intervals:
Softa [21]

In this question, we have to write the set of points from -6 to 3 but excluding -2 and 3 as a union of intervals .

For union, we use U.

For the points that we have to exclude , we put parenthesis on there side  that is  ().

Therefore the required interval form is

[-6,-2)U(-2,3)

As we see that () are used with -2 and 3 . And that's the required interval form .

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3 years ago
Jackie wants to justify that f(x) = 2x - 6 is a linear function. If she evaluated F(x) for consecutive integer values, write a s
NISA [10]

Jackie wants to justify that f(x) = 2x - 6 is a linear function.

Lets assume some values for x  and find out f(x)

We make a table with x values 1, 2, 3, 4 and find f(x)

To find f(x) we plug in x  value in the given equation

x        f(x)

1          2(1)-6 = -4

2         2(2)-6 = -2

3          2(3)-6 = 0

14         2(4)-6 =2

for f(x) we got -4, -2, 0 , 2

The value of f(x) is increasing by 2. There is a constant increase in f(x)

When there is a constant rate of increase then it is a linear function

constant rate of increase that is slope = 2. Hence f(x) = 2x -6 is a linear function.



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3 years ago
Solve the equation: 2^3·2^2
torisob [31]

Answer:

32

Step-by-step explanation:

2^3 * 2^2\\8 * 4\\32

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Step-by-step explanation:

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