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VikaD [51]
3 years ago
8

the variable M varies directly as the cube root of n. when n equals 27 m equals to 216. which equation can be used to find other

combinations of m and n​

Mathematics
1 answer:
Aleks04 [339]3 years ago
5 0

Answer:

A

Step-by-step explanation:

if you divide m by n you get 8

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it's so hard to find it

Step-by-step explanation:

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The theater class production is 75 minutes long. In the production, Leo is on stage for 48% of the 75 minutes. How many minutes
erastova [34]

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36 minutes is the answer!

Step-by-step explanation:

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Simplify.
spin [16.1K]

B. 1.3

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Conditional Distribution, Marginal Distribution, Joint Distribution. <br> What’s the difference?
lutik1710 [3]

Explanation:

Marginal distribution: This distribution gives the probability for each possible value of the Random variable ignoring other random variables. Basically, the values of other variables is not considered in the marginal distribution, they can be any value possible. For example, if you have two variables X and Y, the probability of X being equal to a value, lets say, 4, contemplates every possible scenario where X is equal to 4, independently of the value Y has taken. If you want the probability of a dice being a multiple of 3, you are interested that the dice is either 3 or 6, but you dont care if the dice is even or odd.

Conditional distribution: This distribution contrasts from the previous one in the sense that we are restricting the universe of events to specific condition for other variable, making a modification of our marginal results. If we know that throwing a dice will give us a result higher than 2, then to in order to calculate the probability of the dice being a multiple of 3 using that condition, we have two favourable cases (3 and 6) from 4 total possible results (3,4,5 and 6) discarding the impossible values (1 and 2) from this universe since they dont match the condition given (note that the restrictions given can also reduce the total of favourable cases).

The joint distribution calculates the probabilities for two different events (related to two different random variables) occuring simultaneously. If we want to calculate the joint probability of a dice being multiple of 3 and greater than 2 at the same time, our possible cases in this case are 3 and 6 from 6 possible results. We are not discarding 1 or 2 as possible results because we are not assuming, that the dice is greater than 2, that is another condition that we should met in the combination of events.

3 0
3 years ago
Write 15+45 as a product of two factors using the gcf and the distributive property
valkas [14]

Answer:

15(1 + 3)

Step-by-step explanation:

15 written in its prime factors is 3 × 5 (15 × 1)

45 written in its prime factors 3 × 3 × 5 (15 × 3)

The greatest common factor is 15: 15 × 1 = 15 and 15 × 3 is 45

∴ 15 + 45 = 15(1 + 3)

Hope this helps! Make me brainiest, lol it's fine if you don't. : )

5 0
2 years ago
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