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3 years ago

The quotient of 3.1 divided by 5.

Mathematics

1 answer:

lord [1]3 years ago

6 0

3.1/5 = 0.62 divide 5 into the 3 =0 divide 5 into 31 =6 bring down the 1add a zero

divide 5 into 10 = 2 answer is 0.62

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Help me please I need the answer

Verdich [7]

Answer:

141

Step-by-step explanation:

162+54-75=141

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3 years ago

Maranda earns $42 in three hours Jabrill earn $78 in six hours which worker earns more per hour

RoseWind [281]

Answer:

jabrill

Step-by-step explanation:

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3 years ago

Can someone help me out with this ??

nalin [4]

Answer:

1. b > -2

2. x <= 3

Step-by-step explanation:

Question 1:

-2(b + 5) < -6

Divide both sides by -2. Remember to change the inequality sign.

b + 5 > 3

Subtract 5 from both sides.

b > -2

Question 2:

-(x - 10) >= 7

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4 years ago

What is the product of 115 and 22?

Bess [88]

Answer :D

2530

Question explanation:

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<em>I'm truly sorry if this is incorrect - Answered by Lilo</em>

8 0

2 years ago

For the funtion f(x)= (x+7)^5, Find f^-1 (x)

quester [9]

Answer:

The inverse of function $f(x)= (x+7)^5$ is $\mathbf{f^{-1} (x)=\sqrt[5]{x}+7}$

Option A is correct option.

Step-by-step explanation:

For the function $f(x)= (x+7)^5$ , Find $f^{-1} (x)$

For finding inverse of x,

First let:

$y=(x+7)^5$

Now replace x with y and y with x

$x=(y+7)^5$

Now, solve for y

Taking 5th square root on both sides

$\sqrt[5]{x}=\sqrt[5]{(y+7)^5}\\\sqrt[5]{x}=y+7\\=> y+7=\sqrt[5]{x}\\y=\sqrt[5]{x}-7$

Now, replace y with $f^{-1} (x)$

$f^{-1} (x)=\sqrt[5]{x}+7$

So, the inverse of function $f(x)= (x+7)^5$ is $\mathbf{f^{-1} (x)=\sqrt[5]{x}+7}$

Option A is correct option.

6 0

3 years ago