I assume you're asked to solve
4 cos²(<em>x</em>) - 7 cos(<em>x</em>) + 3 = 0
Factor the left side:
(4 cos(<em>x</em>) - 3) (cos(<em>x</em>) - 1) = 0
Then either
4 cos(<em>x</em>) - 3 = 0 <u>or</u> cos(<em>x</em>) - 1 = 0
cos(<em>x</em>) = 3/4 <u>or</u> cos(<em>x</em>) = 1
From the first case, we get
<em>x</em> = cos⁻¹(3/4) + 2<em>nπ</em> <u>or</u> <em>x</em> = -cos⁻¹(3/4) + 2<em>nπ</em>
and from the second,
<em>x</em> = <em>nπ</em>
where <em>n</em> is any integer.
Answer:
yes, yes
Step-by-step explanation:
B={1,2,3} it doesn't matter if it has ten 2's or one!
so A=B and A⊆B
Answer: 3/11 & 6/10
Step-by-Step explanation:
there are 11 crayons, 3 of which are red so the chance of picking a red one is 3 out of 11. now that you have taken out a crayon you take the original number and take away 1
11 - 1 = 10
so the chance of taking a blue canyon out is 6/10.
these events are dependent because if you didn't take the first crayon out of the supply box the answer would be 6/11 instead of the 6/10 we have
<em><u>Explore Motors dealership has R7 million to spend and wants to buy equal numbers of the entry.</u></em>
Answer:
-8
Step-by-step explanation:
when you substitute -8 for b it is -4(-8)+3=35
-4(-8) is 32 and 32+3=35
Boom.
also btw need help give brainliest
