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kakasveta [241]
4 years ago
15

How do you determine what your grade average is based on the following grades?:

Mathematics
1 answer:
fiasKO [112]4 years ago
5 0

Answer:

Test's average-95

Homework's average-96.67

Step-by-step explanation:

Average is mathematically defined as the sum of the values divided by the total number of values and is expressed as:

\bar X=\frac{1}{n}\sum{x_i}, n=number \ of \ values.

The Tests' average is calculated as:

\bar X_t=\frac{1}{n}\sum{x_i}\\\\=\frac{1}{3}(98+92+95)\\\\=\frac{1}{3}\times 285\\\\=95

Hence, the Tests' average is 95

#The Homework's average is calculated as:

\bar X_h=\frac{1}{n}\sum{x_i}\\\\=\frac{1}{3}(93+97+100)\\\\=\frac{1}{3}\times 290\\\\=96.67

Hence, the Homework's average is 96.67

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A store has a coupon for $10 off and a discount of 20%. Write a function for the coupon. Use x for the original price and C for
Ludmilka [50]
<h2>Explanation:</h2><h2></h2>

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So from the statement 2, you can realize there are two types of discounts:

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Since we need to write a function just for the coupon, then we don't include the discount offered as percentage, then we subtract the coupon from the original price:

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8 0
3 years ago
Solve the equation for all real values of x.<br> cosxtanx - 2 cos x=-1
IceJOKER [234]

Solution to equationcosxtanx - 2 cos^2 x=-1 for all real values of x is  x=2k\pi + \frac{\pi}{6}  , x=2k\pi + \frac{5\pi}{6} .

<u>Step-by-step explanation:</u>

Here we have , cosxtanx - 2 cos^2 x=-1. Let's solve :

⇒  cosxtanx - 2 cos^2 x=-1

⇒  cosx(\frac{sinx}{cosx}) - 2 cos^2 x=-1

⇒  sinx = 2 cos^2 x-1

⇒  sinx = 2 (1-sin^2x)-1

⇒  sinx = 1-2sin^2x

⇒  2sin^2x+sinx-1=0

By quadratic formula :

⇒ sinx = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

⇒ sinx = \frac{-1 \pm \sqrt{1^2-4(2)(-1)} }{2(2)}

⇒ sinx = \frac{-1 \pm3}{4}

⇒ sinx = \frac{1}{2} , sinx =-1

⇒ sinx = sin\frac{\pi}{6} , sinx = sin\frac{3\pi}{2}

⇒ x=\frac{\pi}{6} , x=\frac{3\pi}{2}

But at x=\frac{3\pi}{2} we have equation undefined as cos\frac{3\pi}{2}=0 . Hence only solution is :

⇒ x=\frac{\pi}{6}

Since , sin(\pi -x)=sinx

⇒ x=\pi -\frac{\pi}{6} = \frac{5\pi}{6}

Now , General Solution is given by :

⇒ x=2k\pi + \frac{\pi}{6}  , x=2k\pi + \frac{5\pi}{6}

Therefore , Solution to equationcosxtanx - 2 cos^2 x=-1 for all real values of x is  x=2k\pi + \frac{\pi}{6}  , x=2k\pi + \frac{5\pi}{6} .

3 0
3 years ago
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Answer:

Part A: A linear function because there is a constant rate change.

Part B: y = 760 - 17x

Hope this helps!

4 0
4 years ago
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