Question

Please help asap please ​

Answer 1

Answer:

$a_{5}$ = $\frac{7}{8}$

Step-by-step explanation:

The n th term of a geometric sequence is

$a_{n}$ = a$(r)^{n-1}$

where a is the first term and r the common ratio

Here a = 14 and r = $\frac{-7}{14}$ = - $\frac{1}{2}$, thus

$a_{5}$ = 14 × $(-\frac{1}{2}) ^{4}$ = 14 × $\frac{1}{16}$ = $\frac{14}{16}$ = $\frac{7}{8}$