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umka21 [38]
3 years ago
12

If hexagon JGHFKI Is congruent to hexagon SRTQUV, which pair of angles must be congruent?

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
8 0

Answer:

Angle J and Angle U is fix

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Find f(5) please explain
kirza4 [7]

Answer:

-1

Step-by-step explanation:

A function is represented by the following symbol f(x) where f(x) further represents y like this ,

y=f(x)

so in this question they are asking what is f(5) which means when the value of x is 5 what is the value of y?

We can see in the graph when x = 5 the value of y is -1 to be exact so

f(5) = -1

or

y=f(x)\\-1 = f(5)\\

8 0
3 years ago
Help please <br> 5x-2y=-10
Lena [83]

Answer:

5x - 2y =  - 10 \\ 5x =  - 10 + 2y  \\  x =  \frac{ - 10 + 2y}{5}  \\  \\

when y=0,-5,5,-10,10

then x=-2,-4,0,-6,2

6 0
2 years ago
Roxanne has $80 in a savings account. The interest rate is 10%, compounded annually. To the nearest cent, how much will she have
finlep [7]
104 because 10% of 80 is 8 years meaning 8+8+8=24 add 24 to 80 and ur answer is 104
3 0
3 years ago
There are 10 employees in a particular division of a company. Their salaries have a mean of 570,000, a median of $55,000,and a s
harkovskaia [24]

Answer:

a) $160,000

b) $55,000

c) $332264.804

Step-by-step explanation:

We are given that there are 10 employees in a particular division of a company and their salaries have a mean of $70,000, a median of $55,000, and a standard deviation of $20,000.

And also the largest number on the list is $100,000 but By accident, this number is changed to $1,000,000.

a) Value of mean after the change in value is given by;

     Original Mean = $70,000

       \frac{\sum X}{n} = $70,000  ⇒ \sum X = 70,000 * 10 = $700,000

   New \sum X after change = $700,000 - $100,000 + $1,000,000 = $1600000

  Therefore, New mean = \frac{1600000}{10} = $160,000 .

b) Median will not get affected as median is the middle most value in the data set and since $1,000,000 is considered to be an outlier so median remain unchanged at $55,000 .

c) Original Variance = 20000^{2} i.e.  20000^{2} = \frac{\sum x^{2} - n*xbar }{n -1}

    Original \sum x^{2} = (20000^{2} * (10-1)) + (10 * 70,000) = $3,600,700,000

    New \sum x^{2} = $3,600,700,000 - 100,000^{2} + 1,000,000^{2} = 9.936007 * 10^{11}  

    New Variance = \frac{new\sum x^{2} - n*new xbar }{n -1} = \frac{9.936007 *10^{11}  - 10*160000 }{10 -1} = 1.103999 * 10^{11}    Therefore, standard deviation after change = \sqrt{1.103999 * 10^{11} } = $332264.804 .

7 0
3 years ago
Look at the number line below.
VikaD [51]
Answer: Choice C)

We start at 0 and move 1.4 units to the right. Then we move another 2.3 units to the right to land on 3.7

Notice how 1.4 - (-2.3) = 1.4 + 2.3 = 3.7
5 0
3 years ago
Read 2 more answers
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