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saul85 [17]
3 years ago
13

What are the x- and y- coordinates of point P on the directed line segment from A to B such that P is the length of the line seg

ment from A to B?
(1, 5)  

(0, 3)

(–4, –5)

(–5, –7)
Mathematics
2 answers:
RSB [31]3 years ago
8 0

The correct answer is:

C: (-4, -5)


Hope it helps!


MrMuchimi3 years ago
3 0

Answer:(-4,-5)

Step-by-step explanation:

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22% of 400

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Determine weather it is no solution many solutions or one solutions <br> 3(6-4m)=2(9-6m)
Vinil7 [7]

Answer:

Many solutions

Step-by-step explanation:

7 0
2 years ago
The infinite geometric series S=1+( 2/3 )+( 2/3 )^ 2 +( 2/3 )^ 3 .... equal to:
weqwewe [10]

SOLUTION

The question simply means that we should find the sum to infinity of the geometric series.

The formula of sum to infinity of a geometric serie is given by

S_{\infty}=\frac{a}{1-r}

Where

\begin{gathered} S_{\infty}\text{ is the sum to infinity} \\  \\ a\text{ is the first term = 1} \\  \\ r\text{ is the common ratio = }\frac{2}{3} \end{gathered}

So, this becomes

\begin{gathered} S_{\infty}=\frac{a}{1-r} \\  \\ S_{\infty}=\frac{1}{1-\frac{2}{3}} \\  \\ S_{\infty}=\frac{1}{\frac{3-2}{3}} \\  \\ S_{\infty}=\frac{1}{\frac{1}{3}} \\  \\ S_{\infty}=3 \end{gathered}

Therefore, option b is the correct answer

5 0
1 year ago
Rewrite the form In exponential form:<br> Log100 = x
andrey2020 [161]

Answer:

10^x=100

Step-by-step explanation:

You know how subtraction is the <em>opposite of addition </em>and division is the <em>opposite of multiplication</em>? A logarithm is the <em>opposite of an exponent</em>. You know how you can rewrite the equation 3 + 2 = 5 as 5 - 3 = 2, or the equation 3 × 2 = 6 as 6 ÷ 3 = 2? This is really useful when one of those numbers on the left is unknown. 3 + _ = 8 can be rewritten as 8 - 3 = _, 4 × _ = 12 can be rewritten as 12 ÷ 4 = _. We get all our knowns on one side and our unknown by itself on the other, and the rest is computation.

We know that 3^2=9; as a logarithm, the <em>exponent</em> gets moved to its own side of the equation, and we write the equation like this: \log_3{9}=2, which you read as "the logarithm base 3 of 9 is 2." You could also read it as "the power you need to raise 3 to to get 9 is 2."

One historical quirk: because we use the decimal system, it's assumed that an expression like \log1000 uses <em>base 10</em>, and you'd interpret it as "What power do I raise 10 to to get 1000?"

The expression \log100=x means "the power you need to raise 10 to to get 100 is x," or, rearranging: "10 to the x is equal to 100," which in symbols is 10^x=100.

(If we wanted to, we could also solve this: 10^2=100, so \log100=2)

6 0
2 years ago
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