The total circle has a measure of 2π radian, so this portion is 1/(2π) of the whole circle
the circumference of the whole circle is 2πr
1/(2π) of 2πr=3.07
r=3.07
Answer
Find out the original side length of the square .
To prove
Let us assume that the original length of the square be x.
Formula

As given
The dimensions of a square are altered so that 8 inches is added to one side while 3 inches is subtracted from the other.
Length becomes = x + 8
Breadth becomes = x -3
The area of the resulting rectangle is 126 in²
Put in the formula
(x + 8) × (x - 3) = 126
x² -3x + 8x -24 = 126
x ²+ 5x = 126 +24
x² + 5x - 150 = 0
x² + 15x - 10x - 150 = 0
x (x + 15) -10 (x +15) =0
(x + 15)(x -10) =0
Thus
x = -15 , 10
As x = -15 (Neglected this value because the side of the square cannot be negative.)
Therefore x = 10 inches be the original side of the square.
Answer:68x + 2
Step-by-step explanation:
Answer:
1/3
Step-by-step explanation:
7-9=-2
2-8=-6
2/6 is 1/3 when simplified
Remember, parenthaees are like < and > and brackets ar like ≤ and ≥
domain is how far the x values go
x is left to right
we see they go from -3 to 5, with a filled in dot at -3 and empty dot at 5
means include -3 but not including 5
so like -3≤x<5
or in interval notation
[-3,5) is the domain
range
highest to lowest y value
range is from y=3 to y=-1
we gots full dots so we use brackets
range is [-1,3]
Domain=[-3,5)
Range=[-1,3]
B. read above and understand it