9514 1404 393
Answer:
the correct answer is marked
Step-by-step explanation:
When the graph of the left side of the equation does not intersect the graph of the right side of the equation, there are no solutions.
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<em>Additional comment</em>
Even if you extend the domain to complex numbers, there are no solutions. The f(x) = |x| function always returns a positive real value, even for complex numbers.
Basically if you have an exponent at the end of a 10,
, then in the end the extended notation is going to have 7 zeros. So it'll be 10000000. Then you multiply whats in the rest of the equation together. There's the beginning :) I hope it helps.
Answer:
3/5
4/3
2/1
3/1
Step-by-step explanation:
turn them to ratios and fractions and try to simplify
3/5=3/5
4/3=4/3
2/1=2/1
6/2=3/1
so put the end results in order
so all of them have a bigger numerator than denominator, except one. 3/5. Thats the slowest one.
4/3 isn't quite 2 wholes, but 2/1 is, so 4/3 is second last and 2/1 is second.
3/1 is the first.
Answer:
The numbers are
22 and 23 to solve a problem like this, we need to read and define as we go. Let me explain. So we know that there are two consecutive integers. They can be
x and x+1
. Since their consecutive, one has to be 1
number higher (or lower) than the other. Ok, so first we need "seven times the larger"( 7x+1)
Next, we need to "minus three times the smaller" 7(x+1)−3x
Is equal to " 957(x+1)−3x=95
Alright! There's the equation, now we just need to solve for x! First we are going to get everything on one side and distribute the 7=7x+7−3x−95=4x−88
Pull out a
=4(x−22)Now that we have two terms, we can set them both equal to
0 and solve.4≠0
This can never be true, lets move to the next term (x−22)=0x=
22 That's it! So your two consecutive numbers are
22
