Answer:
the last option or D
Step-by-step explanation:
f(x) > 0 over the interval (-∞, -4)
i hope this helps! quizlet is also very helpful lol, have a wonderful rest of your day/night, xx, nm <3 :)
658,008 i just looked it up and thats what i found.
Let x = the number of dimes
Let y = the number of pennies.
There are 8 coins, therefore
x + y = 8 (1)
The coins are worth 17 cents, therefore
10x + y = 17 (2)
Subtract equation (1) from equation (2).
10x + y - (x + y) = 17 - 8
9x = 9
x = 1
From (1), obtain
y = 8 -x = 8 - 1 = 7
Answer: 1 dime, 7 pennies.
Given: The following functions



To Determine: The trigonometry identities given in the functions
Solution
Verify each of the given function

B

C

D

E

Hence, the following are identities

The marked are the trigonometric identities
Answer:
3
Step-by-step explanation:
there are only x y and z used in the expression no matter how many times they multiply.