-6×-6=36
f-34=36
34+36=70
f=70
1.326 grams of NH3 are required to produce 4.65 g of HF.
Step-by-step explanation:
Balanced chemical reaction is written first to know the number of moles taking part in original reaction.
NH3 +3 F2 ⇒3 HF + NF3
Given:
mass of HF = 4.65
First the number of moles of HF in 4.65 grams is calculated by using the formula:
number of moles (n) = 
atomic mass of HF = 20 grams/mole
putting the values in the above equation number of moles can be found.
n = 
= 0.235 moles of HF are given.
From the equation it can be said that:
1 mole of NH3 reacts to form 3 moles of HF
so, x moles of NH3 would react to form 0.235 moles of HF
= 
3x = 0.235
x = 
x = 0.078 moles of NH3 is required.
The moles are converted to mass by applying the formula:
mass = atomic mass X number of moles (atomic mass of NH3 = 17 grams/mole)
putting the values in the formula
mass = 17 X 0.078
mass = 1.326 grams
Answer:
<u>4 1/12. (Four, one by twelve).</u>
Step-by-step explanation:
7/12 × 7 =?
7/12×7 = <u>49/12.</u>
The answer is now in improper fraction. When we convert it to mixed fraction we get the answer as <u>4 1/12. (Four, one by twelve).</u>
To solve the problem shown bove you must apply the proccedure shown below:
1. You have that:
2a-1<<span>7−1.2a
2a+1.2a<7+1
3.2a<8
a<8/3.2
a<2.5
2. Therefore, f</span><span>or what values of a is the value of the binomial 2a−1 smaller than the value of the binomial 7−1.2a?
</span><span>
As you can see above, the answer for this question is:
All the values of a between -</span>∞ and 2.5<span>
</span>