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Ber [7]
3 years ago
14

Pls help me on this im stuck

Mathematics
2 answers:
Luden [163]3 years ago
8 0

Answer:

44 or B

Step-by-step explanation:

Look at comments above

Evgen [1.6K]3 years ago
4 0
44cm is the correct answer
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The ideal length of a particular metal rod is 20.5 cm. The measured length may vary from the ideal length by at most 0.045 cm. W
tekilochka [14]
To answer this item, we are first to calculate the values of the length of this particular metal rod that is 0.045 cm less than the given,
             Lower limit = 20.5 cm - 0.045 cm = 20.455 cm

Also, we calculate for the upper limit by adding 0.045 cm to the given length. 
            Upper limit = 20.5 cm + 0.045 cm = 20.545 cm

Thus, the answer to this item is D. 
7 0
3 years ago
Read 2 more answers
Anybody know the right answer?
qwelly [4]

Quadrant I : cot(x) > 0 → -cot(x) < 0

Quadrant II : cot(x) < 0 → -cot(x) > 0

Quadrant III : cot(x) > 0 → -cot(x) < 0

Quadrant IV : cot(x) < 0 → -cot(x) > 0

------------------------------------------------------------------

a)\ \left(\dfrac{11\pi}{6},\ -\sqrt3\right)\\\\\dfrac{11\pi}{6}\in\text{Quadrant IV, then -cot(x)} > 0,\ \text{we have}\ -\cot\dfrac{11\pi}{6}=-\sqrt3 < 0

Answer: a)

b)\\\dfrac{2\pi}{3}\in\text{Quadrant II},\ -\cot(x) > 0,\ \text{we have}\ \dfrac{\sqrt3}{3} > 0\\\\c)\\\dfrac{5\pi}{4}\in\text{Quadrant III},\ -\cot(x) < 0,\ \text{we have}\ -1 < 0\\\\d)\\\dfrac{4\pi}{3}\in\text{Quadrant III},\ -\cot(x) < 0,\ \text{we have}\ -\dfrac{\sqrt3}{3} < 0

We know that one answer is only true, so we did not check the correctness of the cotangent value, only to the number sign

8 0
3 years ago
The GCF of 64 and a number is 16. Which of the following could be the number?
Oliga [24]
The number would have to be <u>16</u>.  64 does not divide by 24, 28, or 36 to equal any whole number
6 0
4 years ago
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A child requires a 5ml dose of medicine each day. how many days would a gallon of this medicine last.
OLga [1]

in a US gallon, there are approximately 3.79 Liters, in a Liter there are 1000 milliLiters, so 3.79 Liters is then 3.79 * 1000 milliLiters, namely 3790 milliliters.

since a gallon is then approximately 3790 mL, how many times does 5mL go in to 3790? 3790 ÷ 5 = 758.

since the child uses 5mL in 1 day, then 758 times that is 758 days.

4 0
4 years ago
A shirt costs $45.99 and the whole store is 30% off. Find the sale price of the shirt
jasenka [17]

Answer:

13,7

Step-by-step explanation:

6 0
4 years ago
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