Answer:
m < EAD = 29 degrees
m < CAB = 119 degrees
Given :
The question states that m < CAE = m<FAB = 61 degrees and m<DAF = 90 degrees
Solution:
1. Since line CAF and EAB intersect each other, m<CAF = m< EAF - (opposite vertical angles are equivalent)
2. m<BAC + m<EAC = 180 degrees (sum of linear pair)
3. m<CAB = 180 degrees - m<EAC
4. Equation 1: m<CAB = m<EAF = 119 degrees
5. m<EAF = m<EAD + m< DAF
6. m<EAD = m<EAF - m<DAF
7. m<EAD = 119 degrees-90 degrees = 29 degrees
Hope this helps!!! :)
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Answer:
Answer = 93.6
Step-by-step explanation:
frist multipy 9 x 13 to get 117 than divided it by 2 = 58.5, than times it by 3 since there is three sides.
(58.5 x 3 is 175.5)
Than for the base multipy 7.8 x 9 = 70.2, but since its a tri, divided it by 2 = 35.1.
Add 58.5 and 35.1 to get 93.6
Answer:
seven and sixty-four thousandths
Step-by-step explanation:
in factors it would be
7 x 1
+ 0 x 0.1
+ 6 x 0.01
+ 4 x 0.001
Answer:
D) 0 = 2(x + 5)(x + 3)
Step-by-step explanation:
Which of the following quadratic equations has no solution?
We have to solve the Quadratic equation for all the options in other to get a positive value as a solution for x.
A) 0 = −2(x − 5)2 + 3
0 = -2(x - 5) × 5
0 = (-2x + 10) × 5
0 = -10x + 50
10x = 50
x = 50/10
x = 5
Option A has a solution of 5
B) 0 = −2(x − 5)(x + 3)
Take each of the factors and equate them to zero
-2 = 0
= 0
x - 5 = 0
x = 5
x + 3 = 0
x = -3
Option B has a solution by one of its factors as a positive value of 5
C) 0 = 2(x − 5)2 + 3
0 = 2(x - 5) × 5
0 = (2x -10) × 5
0 = 10x -50
-10x = -50
x = -50/-10
x = 5
Option C has a solution of 5
D) 0 = 2(x + 5)(x + 3)
Take each of the factors and equate to zero
0 = 2
= 0
x + 5 = 0
x = -5
x + 3 = 0
x = -3
For option D, all the values of x are 0, or negative values of -5 and -3.
Therefore the Quadratic Equation for option D has no solution.
Answer:
twice as many as 24 is 48
48+4 = 52
so the answer is 52 . pls make brainliest!
