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shutvik [7]
3 years ago
14

What are two different ways of factoring –3x – 9? Select all that apply. A. –3(x + 3) B. 3(x + 3) C. 3(–x – 3) D. –3(x – 3)

Mathematics
1 answer:
I am Lyosha [343]3 years ago
8 0
The awnser is A) and C)


Hope it helps :)
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What two consecutive numbers have a sum of 53? Thanks! :P
Musya8 [376]
Let's the name the first number x and the consecutive number x + 1. The sum of both of these numbers equals to 53.

We now have our equation:

x + x + 1 = 53

Now solve for x.

x + x + 1 = 53
2x + 1 = 53 <-- Combine like terms
2x = 52 <-- Subtract 1 from each side
x = 26

So, the first number is 26 and the second number is 27.
4 0
3 years ago
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A student needs to earn 80 points on the test in order to keep an A grade for the semester. Write an equation that represents th
Annette [7]
The most simple way is to get 8 questions right on a ten question test. 8q/10q = 80%.
4 0
3 years ago
Which expression(s) are equivalent to (5 1/8 x 5 3/8)^3
Fiesta28 [93]

Answer:

(2703/64)^3

Step-by-step explanation:

hello :

(5 1/8 x 5 3/8)^3 = (51×53/8×8) ^3 = (2703/64)^3

6 0
3 years ago
What are the partail products of 42×28
OLEGan [10]
1,176. Your Welcome!!!
6 0
3 years ago
An automobile manufacturer finds that 1 in every 2500 automobiles produced has a particular manufacturing defect. ​(a) Use a bin
Advocard [28]

Answer:

a) 0.1558 = 15.58% probability of finding 4 cars with the defect in a random sample of 7000 cars.

b) 0.1557 = 15.57% probability of finding 4 cars with the defect in a random sample of 7000 cars. These probabilities are very close, which means that the approximation works.

Step-by-step explanation:

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

To use the Poisson approximation for the binomial, we have that:

\mu = np

1 in every 2500 automobiles produced has a particular manufacturing defect.

This means that p = \frac{1}{2500} = 0.0004

a) Use a binomial distribution to find the probability of finding 4 cars with the defect in a random sample of 7000 cars.

This is P(X = 4) when n = 7000. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{7000,4}.(0.0004)^{4}.(0.9996)^{6996} = 0.1558

0.1558 = 15.58% probability of finding 4 cars with the defect in a random sample of 7000 cars.

(b) The Poisson distribution can be used to approximate the binomial distribution for large values of n and small values of p.

Using the approximation:

\mu = np = 7000*0.0004 = 2.8. So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 4) = \frac{e^{-2.8}*(2.8)^{4}}{(4)!} = 0.1557

0.1557 = 15.57% probability of finding 4 cars with the defect in a random sample of 7000 cars. These probabilities are very close, which means that the approximation works.

6 0
3 years ago
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