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aleksandrvk [35]
3 years ago
13

LOTS OF POINTS AND BRAINLIEST PLEASE HELP

Mathematics
2 answers:
kozerog [31]3 years ago
8 0

Answer:

f(x)=x^3-3x^2+x-3 Graph 2

l(x)=x^2-4x+4 Graph 1

g(x)=x^2-5x+4 Graph 3

The rest, don't use. They don't match.

Step-by-step explanation:

I used my graphing calculator and these were the results that it gave me. I hope that this helps you and I am so so sorry if its wrong.

yarga [219]3 years ago
6 0

Answer:

1) f(x)

2) g(x)

3) h(x)

Step-by-step explanation:

Zero in 1: x = 3

f(3) = 3³ - 3(3²) + 3 - 3 = 0

Zero in 2: x = 1, 4

g(1) = 1² - 5(1) + 4 = 0

g(4) = 4² - 5(4) + 4 = 0

Zero in 3: x = -2

h(-2) = -4(-2) - 8 = 0

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4 years ago
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Sladkaya [172]

Answer:

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Step-by-step explanation:

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3 years ago
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Jose can read 7 pages of his book in 5 minutes. At this rate, how long will it take him to read the entire 175 page book?
il63 [147K]
125 minutes, or 2 hours and 5 minutes.

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4 years ago
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What is the value of the 7 in the number 2 741 203<br><br> give your answer in number
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8 0
3 years ago
A molecule of sodium carbonate contains 2 atoms of sodium to every 3 atoms of oxygen. Could a compound containing 12 atoms of so
artcher [175]

Answer:

No, a compound containing 12 atoms of sodium and 15 atoms of oxygen could not be sodium carbonate. When its ratio of atoms is reduced to the lowest terms, it is not the same as sodium carbonate. 4:5 ≠ 2:3

Step-by-step explanation:

Use ratios to solve this problem.

In sodium carbonate, the ratio for the number of atoms for sodium to oxygen (sodium:oxygen) is 2:3.

Check if the ratio for the compound with the ratio 12:15 is equal to 2:3.

Reduce the ratio 12:15 to lowest terms, just like how you would reduce a fraction. Find the GCF (greatest common factor). The left and right sides are both divisible by 3.

12/3 = 4

15/3 = 5

The ratio in the compound is 4:5.

4:5 ≠ 2:3

Since the ratios are not the same, the compound is not sodium carbonate.

3 0
4 years ago
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