Here, the union tells us that at least one of the original inequalities must be true. We solve each separately, first.
x + 2 < 5 OR x - 7 > -6
x < 3 OR x - 7 > -6 subtract 2 on both sides of the equation left of the OR
x < 3 OR x > 1 add 7 on both sides of the equation right of the OR
Thus x < 3 or x > 1. In set notation, {x | x < 3 or x > 1} is true.
I’m pretty sure it would be f(x)= -5/2x-8
You can honestly plug it into a graph yourself or you can get the formula and solve it like that. Unfortunately I do not have the formula on hand. Sorry
Answer:Convert to radical form using the formula a x n = n √ a x . Exact Form: 7 √ ( − 4 ) 2 Decimal Form: 1.48599428 … .
Step-by-step explanation:
Answer:
I think it would be fine if they notified you but only if they used me for a good reason.
<em>On the other hand...</em>
no matter if it's on the agreement if it is inappropriate on your part it is illegal and you can complain.
Answer:
[x + 3][2x² - 7]
Step-by-step explanation:
Start out by doing this: [2x³ + 6x² ] - [7x - 21]
↑ ⤻ ↑
GCF: 2x² GCF: -7
Do as so: 2x²[x + 3] -7[x + 3]
You see, one factor is already found [x + 3]. You only use it ONCE. Now, the other factor comes from your two Greatest Common Factors from both groups [2x² - 7]. Together, you end up with the above answer. That arrow under the negative tells you that it is attached to the 3 [distribution of the negative].
Well, I am joyous to assist you anytime.