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4 years ago

21 divided by $13.65

Mathematics

2 answers:

raketka [301]4 years ago

6 0

The answer is 0.65. I hope this helps!

liraira [26]4 years ago

6 0

First you convert $13.65 into a regular Number then you would do 13.65 divided by 21 and you will Getafe 65. Since you have $13.65 as a desimal your actual answer would be .65

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Ilia_Sergeevich [38]

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3 years ago

Write a linear equation that contains the ordered pair shown in the table below:

Amiraneli [1.4K]

Answer:

$y=2x-4$

Step-by-step explanation:

Let the equation of line is $y=mx+b$ , where $m$ is the slope of the line.

It passes through $(-5,-14),(-2,-8)\ and\ (1,-2)$ .

(<em>Slope of the line</em> joining $(x_1,y_1)\ and\ (x_2,y_2)=\frac{y_2-y_1}{x_2-x_1}$ )

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Check if $(-5,-14)$ is on the line $y=2x-4$

$L.H.S.=-14\\R.H.S.=2\times (-5)-4=-10-4=-14\\L.H.S.=R.H.S.$

Hence line passes through $(5,-14)$ .

Check if $(-2,-8)$ is on the line $y=2x-4$

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3 years ago

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3 years ago

The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.

MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle = $3\times\ side$

$3\times\ side$ $=[tex]81\sqrt{3}$

$Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm$

Thus from the diagram , Side $AB=BC=AC= 27\sqrt{3} \ cm$

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus $\angle OBC = 30$ °

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

$tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2} } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\$

Thus ,apothem OE= 13.5 cm

Now for radius,

We consider ΔOBE

$cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB} \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm$

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

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3 years ago

The safety inspector notes that Ray also needs to plan for a vertical ladder through the center of the coaster's parabolic shape

jarptica [38.1K]

You can rearrange f(x) as:

f(x) = 3(x^2 + 3x) + 12 = 3(x+1.5)^2 +5.25

So you can see the vertex is at (0,5.25) when x = -1.5

The axis of symmetry then lies in x = -1.5

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3 years ago

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