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Usimov [2.4K]
2 years ago
6

sal works for a computer repair shop. he has determines that customers pay on average $150 for each computer they bring in. He p

ays $2000 per month in rent, and each computer he fixed requires $75 in parts and labor to fix. how many computers must sal repair in one year in order to break even?
Mathematics
1 answer:
Effectus [21]2 years ago
3 0

Answer:

The answer is :

sal must repair 320 computers in a year to break even.

Step-by-step explanation:

The break even point in a business is the point at which the total costs and the total revenue in a business are equal.

In order to calculate sal's break even point, we will first of all calculate the total costs incurred during the business year, then using the selling price (repairing price), we will calculate how many computers will be repaired to reach the incurred cost. This is done as follows:

Rent per month = $2,000

∴ Rent for a year (12 months) = 2,000 × 12 = $2,400

Cost incurred in fixing each computer = $75

Priced charged for fixing each computer = $150

Next, since we know that sal requires $75 in parts and labor to fix a computer, we will calculate the net price charged for each computer fixed as follows:

Net price charged = Priced charged for fixing each computer - Cost incurred in fixing each computer

Net price charged = 150 - 75 = $75

Finally to calculate the break even point, we know the net income (net price charged) for each computer and the costs of rent for each year, therefore, we will divide the cost incurred by the net price charged, as follows:

break even point = cost of rent for one year ÷ net price charged

break even point = 24,000 ÷ 75 = 320 computers.

Therefore, by the time sal repairs 320 computers during the year, he must have covered the costs incurred in operations, every additional repair, becomes a profit.

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Emma buys and sells truck parts she bought two tires for $35 eachand later sold them for $65 each she bought three rims for $75
alexdok [17]

Answer:2X35=70 2X65=130 130-70=60   So 60 dollars profit for the two tires.

3X75=225 3X136=408 408-225=183  So 183 dollars profit for the three rims

5X4=20 5X15=75 75-20=55  So 55 dollars profit for the headlights.  

Total profit  60+183+55=298

  Step-by-step explanation:

 

5 0
2 years ago
If working together, brothers Tom and Jack can paint a wall in 4 hours, how much time would it take Jack to paint the wall alone
kiruha [24]
T+J=4 hours
x+2x=4 hours
3x=240 minutes
X=80 minutes
3 0
3 years ago
Carrie is buying bulk candy for a high school fundraiser. She buys 1000 candy bars for $350. What is the unit cost per candy bar
liubo4ka [24]
1000 candy bars ... $350
1 candy bar ... $x = ?

If you would like to know what is the unit cost per candy bar, you can calculate this using the following steps:

1000 * x = 350 * 1
1000 * x = 350    /1000
x = 350 / 1000
x = $0.35

Result: She can buy 1 candy bar for $0.35, so the correct result would be B) $.35.
6 0
3 years ago
The mayor of a town has proposed a plan for the construction of an adjoining bridge. A political study took a sample of 13001300
Ket [755]

Answer:

No, there is not enough evidence at the 0.02 level to support the strategist's claim.

Step-by-step explanation:

We are given that a political study took a sample of 1300 voters in the town and found that 57% of the residents favored construction.

And, a political strategist wants to test the claim that the percentage of residents who favor construction is more than 54%, i.e;

Null Hypothesis, H_0 : p = 0.54 {means that the percentage of residents who favor construction is 54%}

Alternate Hypothesis, H_1 : p > 0.54 {means that the percentage of residents who favor construction is more than 54%}

The test statistics we will use here is;

                 T.S. = \frac{\hat p -p}{\sqrt{\frac{\hat p(1- \hat p)}{n} } } ~ N(0,1)

where, p = actual percentage of residents who favor construction = 0.54

           \hat p = percentage of residents who favor construction in a sample of

                  1300 voters = 0.57

           n = sample of voters = 1300

So, Test statistics = \frac{0.57 -0.54}{\sqrt{\frac{0.57(1- 0.57)}{1300} } }

                              = 2.185

Now, at 0.02 significance level, the z table gives critical value of -2.3263 to 2.3263. Since our test statistics lie in the range of critical values which means it doesn't lie in the rejection region, so we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the percentage of residents who favor construction is 54% and the strategist's claim is not supported.

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krek1111 [17]

Answer:

Step-by-step explanation:

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