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Ira Lisetskai [31]
3 years ago
11

Explain why a linear function that is continuous has an infinite number of solutions. Then determine which of the following repr

esentations show all the solutions of the function: a table, a graph, or an equation. Explain
Mathematics
1 answer:
lozanna [386]3 years ago
3 0
Bc lines go on forever.
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Write the explicit formula for the arithmetic sequence.<br><br> 2, -2, -6, -10, -14, ...
melisa1 [442]
2-6=4/8 but I’m not really sure though
4 0
3 years ago
6) Solve:<br> 5x + 12 + 3x = 8x - 5
svet-max [94.6K]

Answer: −17

Step-by-step explanation: ez

5 0
3 years ago
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Sam deposits 12,500 each year into a retirement account with a %3 simple interest rate. If he deposits the same amount each year
alina1380 [7]

The money in bank after 4 years will be \bold{\$68125}

<u>Solution:</u>

Given, Sam deposits 12,500 each year into a retirement account with a \%3 simple interest rate.  

He deposits the same amount each year, we have to find the amount of money will he have at the end of his fourth year.

We know that, \text { Simple Interest }=\frac{\text {Amount } \times \text { Rate } \times \text { Time}}{100}

So, now let us find S.I after 1^{\mathrm{st}} \text{ year } =\frac{12500 \times 3 \times 1}{100}=125 \times 3=375

Then, after 1^{\text {st }} year he adds 12,500 again, which means amount doubles \rightarrow S.I also doubles as rate and time of 1 year gap are constant.

Then, S.I for 2^{\text {nd}} \text {year }=375 \times 2=750

Amount and corresponding S.I for 4 years will be,

\begin{array}{l}{12500 \rightarrow 375} \\\\ {25000 \rightarrow 750} \\\\ {37500 \rightarrow 1125} \\\\ {50000 \rightarrow 1500} \\\\ {62500 \rightarrow 1875}\end{array}

Now, total balance = amount after 4^{th} year + sum all simple interests made up to now.

Total balance = 62500 + (375 + 750 + 1125 + 1500 + 1875) = 62500 + 5625 = 68125

6 0
3 years ago
Read 2 more answers
The value of a car is depreciating at a rate of 5% per year. In 2010, the car was worth $32,000. Find the value of the car in 20
PSYCHO15rus [73]

Data:

Depreciating: The value decrease

Rate: 5% per year

2010: $32,000

2013: $?

Step 1: As depreciating means decrease, the value of the car is decaying

Step 2 and step 3: You use the formula below to find the value of the car after 3 years (as the value is decaying the rate in the formula is substracting)

Final value: F

Principal value: P=32000

rate: r=5

Time in years: n=3 (2013-2010=3)

\begin{gathered} F=P(1-\frac{r}{100})^n \\  \\ F=32000(1-\frac{5}{100})^3 \\  \\ F=32000(0.95)^3 \\  \\ F=27436 \end{gathered}

In 2013 the value of the car is $27,436
8 0
10 months ago
Instruction
natulia [17]

Answer:

Step-by-step explanation:

Your question has typographical errors. The equation is 2a + b = 15.7, not 2e+b-15.7

2a + b = 15.7

b = 15.7  - 2a

since a > b, a = 6.3 cm

b = 15.7 - 2·6.3 = 3.1 cm

3 0
3 years ago
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