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kap26 [50]
3 years ago
14

Why does this graph have a strong correlation?

Mathematics
2 answers:
Luda [366]3 years ago
8 0
It has a strong correlation cause it goes through the origin. 
kompoz [17]3 years ago
3 0
It goes through the origin and is a positive slope
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write a function g whose graph represents a translation 2 units to the right followed by a horizontal stretch by a factor or 2 o
Alenkinab [10]
\bf f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}\\\\
f(x)=&{{  A}} \left|{{ B }}x+{{  C}}  \right|+{{  D}}
\\\\
--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind, let's see,
 
\bf f(x)=|x| \implies \begin{array}{lllccll}
f(x)=&1|&1x&+0|&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}

so, to shift it to the right by 2 units, simply set C = 2.
to stretch it by 2, set A = 1/2.

the smaller A is, the wider it opens, the larger it is, the more it shrinks.
5 0
3 years ago
Assume that​ women's heights are normally distributed with a mean given by mu equals 62.5 in​, and a standard deviation given by
kirza4 [7]

Answer: a) The probability is approximately = 0.5793

b) The probability is approximately=0.8810

Step-by-step explanation:

Given : Mean : \mu= 62.5\text{ in}

Standard deviation : \sigma = \text{2.5 in}

a) The formula for z -score :

z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}

Sample size = 1

For x= 63 in. ,

z=\dfrac{63-62.5}{\dfrac{2.5}{\sqrt{1}}}=0.2

The p-value = P(z

0.5792597\approx0.5793

Thus, the probability is approximately = 0.5793

b)  Sample size = 35

For x= 63 ,

z=\dfrac{63-62.5}{\dfrac{2.5}{\sqrt{35}}}\approx1.18

The p-value = P(z

= 0.8809999\approx0.8810

Thus , the probability is approximately=0.8810.

6 0
3 years ago
which is not a result of multiplying the height of a rectangular prism by a scale factor of 1/2 and I need work to
chubhunter [2.5K]
C is the answer


for example

assume that the height of a rectangular prism is 2, width is 1 and length measures 3

the volume will be 6
(2*1*3)

if we multiply height with the scale factor of 1/2
it becomes 1

so the volume will be 3
(1*1*3)

this situation goes for other examples, too


good luck
5 0
3 years ago
Here’s the answer you need to know
vovikov84 [41]
Thank you sooo much Maddi441
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2 years ago
James had a large bag of raisins. He ate
Sergio039 [100]

Answer:

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2 years ago
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