Answer:
t= -1.33 recurring and -2
Step-by-step explanation:
3t²+4t+8=-6t
3t²+4t+6t+8
3t²+10t+8
This is a quadratic equation, it can be solved by using either factorisation, completing the square method or formulae method. For the purpose of this question, I would be using the formulae method.
-b±√(b²-4ac)/2a
Where a=3, b= 10 and c=8
-10±√(10²-4(3)(8))/2(3)
-10±√(100-96)/6
(-10±√4)/6
(-10±2)/6
-10+2/6 or -10-2/6
-8/6 or -12/6
-1.3333 recurring or -2
Answer: Does not exist.
Step-by-step explanation:
Since, given function, f(x) = 6x tan x, where −π/2 < x < π/2.
⇒ f(x) = 
And, for vertical asymptote, cosx= 0
⇒ x = π/2 + nπ where n is any integer.
But, for any n x is does not exist in the interval ( -π/2, π/2)
Therefore, vertical asymptote of f(x) where −π/2 < x < π/2 does not exist.
Answer:
18
Step-by-step explanation:
7 - 5 = 2
triangle = bh/2
triangle = 2(3) / 2
triangle = 3
rect = bh
rect = 3 x 5
rect = 15
trapezoid = 15 + 3
trapezoid = 18
Answer:
x = - 4, x = 6
Step-by-step explanation:
To find the x- intercepts let y = 0 , that is
- 3(x + 4)(x - 6) = 0
Equate each factor to zero and solve for x
x + 4 = 0 ⇒ x = - 4
x - 6 = 0 ⇒ x = 6
