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Yuri [45]
3 years ago
13

Jared painted 5/12 and 4/12 blue.what part of the mug is not red or blue?

Mathematics
1 answer:
Reika [66]3 years ago
7 0
3/12 of the mug is not blue or red
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HELP, I WILL GIVE BRAINLIEST!
denis23 [38]
I think it’s C. I don’t know though.
8 0
3 years ago
If h(x) = 3x + 1 and g(x) = 10 − x2, find h[g(2)<br> Show work please!Thanks!
Nataliya [291]

Answer:

the answer is 19.............

6 0
2 years ago
Can someone help please
REY [17]

Answer:

<em>HT </em>= 17

<<em>T</em> = 62°

<<em>H</em> = 28°

Step-by-step explanation:

1. Use the Pythagorean Theorem to find the length of the missing side.

a² + b² = c²

15² + 8² = c²

225 + 64 = c²

289 = c²

√289 = c

c = 17

The length of side HT is 17.

2. Use SOHCAHTOA to find the measure of <<em>T</em>. Since we know the measure of two sides, opposite (15) and adjacent (8), use the formula for tangent as tangent is opposite/adjacent.

Tangent = \frac{opposite}{adjacent}  = \frac{15}{8} = 1.875

Use the tan⁻¹ button on the calculator to find the value for <<em>T.</em>

tan⁻¹(1.875) = 61.9°

<<em>T = </em>62°

3. To find the measure of <<em>H, </em>you can either add up the two angles and subtract from 180° or use SOHCAHTOA.

90° + 61.9° + x = 180°

151.9° + x = 180°

x = 28°

or

We know two sides: opposite (8) and adjacent (15). So, we will use tangent.

Tangent = \frac{opposite}{adjacent} =  \frac{8}{15} = 0.5333333333

Take the tan⁻¹ to get the measure of <<em>H.</em>

tan⁻¹(0.5333333333) = 28.07 = 28°

Hope this helps. Please give a thanks and mark as brainliest. :)

6 0
3 years ago
The coordinates of quadrilateral ABCD are A(-1,-5), B(8,2), C(11,13), and D(2,6). Using coordinate geometry, prove that quadrila
Sliva [168]

Answer:

The quadrilateral ABCD is a rhombus.

Step-by-step explanation:

A rhombus is a quadrilateral having equal sides.

If ABCD is a rhombus then,

AB = BC = CD =  DA

It is provided that the coordinates of the rhombus ABCD are:

A = (-1, -5)

B = (8, 2)

C = (11, 13)

D = (2, 6)

Use the distance formula to compute the lengths of AB, BC, CD and DA.

The distance formula is:

d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

Compute the length of AB:

AB=\sqrt{(8-(-1))^{2}+(2-(-5))^{2}}=\sqrt{130}=11.4

Compute the length of BC:

BC=\sqrt{(11-8)^{2}+(13-2)^{2}}=\sqrt{130}=11.4

Compute the length of CD:

CD=\sqrt{(2-11)^{2}+(6-13)^{2}}=\sqrt{130}=11.4

Compute the length of DA:

DA=\sqrt{(2-(-1))^{2}+(6-(-5))^{2}}=\sqrt{130}=11.4

Thus, the lengths AB, BC, CD and DA are equal, i.e. all sides are of length 11.4.

Hence proved that the quadrilateral ABCD is a rhombus.

7 0
3 years ago
Write the fractions as a percent. If neccisary, round to the nearest tenth of a percent For both.
butalik [34]

9/15 as a percent is 60%, so D.

4 1/5 as a percent is 420%,  so B.

8 0
3 years ago
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