How do you take the antiderivative of (sinxcosx)^2?

1 answer:

8 0

∫(sinx cosx)^2dx = ∫(1/2sin 2x)^2 dx = 1/4∫sin^2 2x dx = 1/4∫1/2(1 - cos 4x)dx = 1/8∫(1 - cos 4x) dx = 1/8[x - sin 4x / 4] + c = 1/32(4x - sin 4x) + c

You might be interested in

Plz Help. write as polynomial -a²(3a-5)+4a(a²-a)

Genrish500 [490]

Answer:

a^3 + a^2

Step-by-step explanation:

Distribute the term left of each set of parentheses, then combine like terms.

-a²(3a - 5) + 4a(a² - a) =

= -3a^3 + 5a^2 + 4a^3 - 4a^2

= a^3 + a^2

3 0

2 years ago

How do you turn fractions into decimals?

Anvisha [2.4K]

Step 1: Find a number you can multiply by the bottom of the fraction to make it 10, or 100, or 1000, or any 1 followed by 0s.

Step 2: Multiply both top and bottom by that number.

Step 3. Then write down just the top number, putting the decimal point in the correct spot (one space from the right hand side for every zero in the bottom number)

7 0

3 years ago

HURRY!!!!!!!!! Given P(5,10,8) and Q(7,11,10), find the midpoint of the segment PQ.

rusak2 [61]

Answer:

$P_{m}=(6,10.5,9)$