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3 years ago

Please help me (picture)

Mathematics

1 answer:

kirill [66]3 years ago

5 0

Answer:the answer is c

Step-by-step explanation:

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Find the mean deviation of 3 ,6 ,6,7,8,11,15,16

solniwko [45]

Answer:

Given data :

3 ,6 ,6 ,7 ,8 ,11 ,15 ,16

Data is already in ascending order so let's start answering.

We have to find the mean of Given data

$\sf \: Mean = \frac{sum \: of \: all \: observations}{number \: of \: observations} \\$

$\sf \: mean = \frac{3 + 6 + 6 + 7 + 8 + 11 + 15 + 16}{8} \\ \\ \sf \: mean = \cancel \frac{72}{8} \\ \\ \red{\underline{ \boxed{ \sf \: mean = 9}}}$

Mean of Given data is 9

5 0

3 years ago

What is the area of a circle that has a circumference of 42 inches? A. 140.4 in2 B. 126.60 in2 C. 132.62 in2 D. 21.04 in2

tankabanditka [31]

Circumference = 2 $\pi$ r
   42 = 2 $\pi$ r
42/(2 $\pi$ ) = r
21/ $\pi$ = r

Area = $\pi$ r²
   = $\pi$ (21/ $\pi$ )²
   = 21²/ $\pi$
   = 140.37
   ≈ 140.4

Answer: A

7 0

3 years ago

If a function is defined by the formula y equals 2x + 1 + that domain is given by the set 3, 5, 7, 9 then which set represents t

Mariulka [41]

Answer:

{7, 11, 15, 19}

Step-by-step explanation:

The function is defined by the formula y = 2x + 1 ........ (1)

Now, domain of the function are given to be {3, 5, 7, 9}

Hence, from equation (1), at x= 3, y = 2 × 3 + 1 = 7

Now, at x = 5, y = 2 × 5 + 1 = 11

Again, at x = 7, y = 2 × 7 + 1 = 15

Finally, at x = 9, y = 2 × 9 + 1 = 19

Therefore, the range of the corresponding domain of this function is given to be {7, 11, 15, 19}. (Answer)

8 0

3 years ago

Solve for x.<br> x + 5 > 4

Delvig [45]

Answer:

x > -1

Step-by-step explanation:

Isolate the variable, x. Treat the > sign like an equal sign, what you do to one side, you do to the other.

Subtract 5 from both sides:

x + 5 (-5) > 4 (-5)

x > 4 - 5

x > -1

x > -1 is your answer.

8 0

3 years ago

Read 2 more answers

Use the identity (x2+y2)2=(x2−y2)2+(2xy)2 to determine the sum of the squares of two numbers if the difference of the squares of

fomenos

Answer:

The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>

Step-by-step explanation:

Given : the difference of the squares of the numbers is 5 and the product of the numbers is 6.

We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Since, given the difference of the squares of the numbers is 5 that is $(x^2-y^2)^2=5$

And the product of the numbers is 6 that is $xy=6$

Using identity, we have,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Substitute, we have,

$(x^2+y^2)^2=(5)^2+(2(6))^2$

Simplify, we have,

$(x^2+y^2)^2=25+144$

$(x^2+y^2)^2=169$

Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

5 0

3 years ago

Read 2 more answers