PLEASE HELP WILL NAME BRAINLIEST!!!!!

there were twenty one adults in line at a movie theater.That is three times the number of children in line. how many children we

V125BC [204]

You would do 21 divided by 3 and get 7.

The answer is 7 kids are in the line.

Please vote my answer the brainiest if it was helpful!!

7 0

3 years ago

A jeweler had a fixed amount of gold to make bracelets and necklaces. The amount of gold in each bracelet is 6 grams and the amo

nikitadnepr [17]

Answer:

The jeweler made 11 bracelets and 7 necklaces.

Step-by-step explanation:

Given that a jeweler had a fixed amount of gold to make bracelets and necklaces, and the amount of gold in each bracelet is 6 grams and the amount of gold in each necklace is 16 grams, knowing that the jeweler used 178 grams of gold and made 7 more necklaces than bracelets, to determine a system of equations that could be used to determine the number of bracelets made and the number of necklaces made, the following mathematical reasoning should be considered:

(16 - 6) x 7 = 70

178 - 70 = 108

108/6 = 18

18 - 7 = 11

(11 x 6) + (7 x 16) = X

66 + 112 = X

178 = X

Thus, the jeweler made 11 bracelets and 7 necklaces.

4 0

3 years ago

From a group of 13 women and 12 men, a researcher wants to randomly select 8 women and 8 men for a study. In how many ways can

Fantom [35]

The total number of ways the study can be selected is: 637065

Given,

Total number of women in a group= 13

Total number of men in a group = 12

Number of women chosen = 8

Number of men chosen = 8

∴ the total number of ways the study group can be selected = 13C₈ and 12C₈.

This in the form of combination factor = nCr

∴ nCr = n!/(n₋r)! r!

13C₈ = 13!/(13 ₋ 8)! 8!

= 13!/5!.8!

= 1287

12C₈ = 12!/(12₋8)! 8!

= 12!/5! 8!

= 495

Now multiply both the combinations of men and women

= 1287 × 495

= 637065

Hence the total number of ways the study group is selected is 637065

Learn more about "Permutations and Combinations" here-

brainly.com/question/11732255

#SPJ10

4 0

2 years ago

Need help please help me

ANTONII [103]

Megan:
x to the one third power = $x ^{1/3}$
x to the one twelfth power = $x ^{1/12}$

The quantity of x to the one third power, over x to the one twelfth power is:
 $\frac{x ^{1/3}}{x ^{1/12}}$

Since $\frac{ x^{a} }{ x^{b} } = x ^{a-b}$
then $\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12}$

Now, just subtract exponents:
1/3 - 1/12 = 4/12 - 1/12 = 3/12 = 1/4

$\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12} = x^{1/4}$

Julie:
x times x to the second times x to the fifth = x * x² * x⁵

The thirty second root of the quantity of x times x to the second times x to the fifth is
 $\sqrt[32]{x* x^{2} * x^{5} }$

Since $x^{a}* x^{b}= x^{a+b}$
Then $\sqrt[32]{x* x^{2} * x^{5} }= \sqrt[32]{ x^{1+2+5} } =\sqrt[32]{ x^{8} }$

Since $\sqrt[n]{x^{m}} = x^{m/n} }$
Then $\sqrt[32]{ x^{8} }= x^{8/32} = x^{1/4}$

Since both Megan and Julie got the same result, it can be concluded that their expressions are equivalent.

3 0

3 years ago

Find a polynomial f(x) of degree 4 that has the following zeros. 0, -5, 8, -2

Roman55 [17]

Answer:

The polynomial of the function degree '4'

x⁴ - x³ -46 x² -80x =0

Step-by-step explanation:

Explanation:-

Given zeros are 0 ,-5,8,-2

x =0 , x=-5 ,x=8 and x=-2

(x-0) , ( x+5) , (x-8) and (x+2)

The polynomial function with degree '4'

(x-0)(x-(-5)(x-8)(x-(-2) =0

x ( x+5) (x-8) (x+2) =0

(x² +5x)(x-8)(x+2) =0

(x³ -8 x²+5x² -40 x)(x+2) =0

( x³ -3 x² - 40 x) (x +2) =0

x⁴ + 2 x³ - 3 x³- 6 x²-40 x²- 80 x =0

x⁴ - x³ -46 x² -80x =0

Final answer:-

The polynomial of the function degree '4'

x⁴ - x³ -46 x² -80x =0

3 0

3 years ago