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melisa1 [442]
3 years ago
14

The United Air Force has 19 women for every 81 men enlisted. If a squadron has 250 members, approximately how many men are men?

Mathematics
2 answers:
Volgvan3 years ago
6 0
Answer : men :203, & women: 47
zmey [24]3 years ago
5 0

Answer:

Approximately the number of men is 203 and number of women is 47.

Step-by-step explanation:

It is given that the United States Air Force has 19 women for every 81 men enlisted.

It means the ratio between men and women is 81:19.

Sum of ratio is

Therefore for each 100 people, there are 81 men and 19 women.

Total number of peoples is 250.

In 250 members the number of men is

The numbers of persons cannot be a fraction values or a decimal value, therefore the number of men is 203.

In 250 members the number of women is

Therefore approximately the number of men is 203 and number of women is 47.

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Calculate using Cauchys integral formula
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Answer:

9πi/2

Step-by-step explanation:

\oint\limits_C {\frac{5z^{2}+4}{(z-1)(z+3)} } \, dz,\ C: |z|=2

Let f(z) = (5z² + 4) / (z + 3).

\oint\limits_C {\frac{f(z)}{z-1} } \, dz,\ C: |z|=2

Using Cauchy's integral formula:

2\pi i\ f(1)\\2\pi i\ (\frac{5(1)^{2}+4}{1+3}) \\2\pi i\ (\frac{9}{4}) \\\frac{9\pi i}{2}

5 0
2 years ago
PLZ PLZ HELP ME WILL GIVE 100 pts ASAP (also brainliest to the user with a better answer
andrezito [222]
Divide the angle into two equal (congruent) parts without actually measuring the angle.
4 0
3 years ago
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Suppose that an individual has a body fat percentage of 15.9% and weighs 159. How many pounds of her weight is made up of fat? R
Anna007 [38]

Answer:

25.3 lb

Step-by-step explanation:

We can multiply the whole by the percentage to find the part. Since 15.9% is equal to 0.159, the weight of fat is 159*0.159 = 25.281. Round this to the nearest tenth, and we get 25.3 pounds.

5 0
1 year ago
2. El perimetro de un rectangulo es 64 pies. Su largo es 12 pies mas que 3 veces su ancho. Halla las dimensiones del rectangulo
Afina-wow [57]
Ancho= x
Largo= 3x+12 ("12 pies más (adición) que 3 veces (multiplicación) su ancho (x)")

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(3x+12)+(3x+12)+x+x=64
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x=40/8
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Luego lo único que queda hacer es substituir el valor de x en cada ecuación para calcular los valores que te piden.



4 0
2 years ago
A car valued at £18000 at the start of 2017, depreciated in value by 5% each year for 3 years. How much did it lose in value ove
Anna11 [10]

<u>Answer:</u>

The amount lost over the 3 years s 2567.25£  

<u>Explanation:</u>

$\mathrm{F}=\mathrm{I} \times\left(1-\left(\frac{r}{100}\right)\right)^{\mathrm{n}}$

where F = final value after n years

I = initial value of the car in 2017 = £18000 (given)

Since the value is depreciated 5% every year for 3 years,

r = percentage rate of depreciation = 5% (given)

n = 3 years

Substituting these values in formula, we get

$\mathrm{F}=18000 \times\left(1-\frac{5}{100}\right)^{3}$

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 = 15432.75£ which is the value of the car after 3 years

Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.  

6 0
3 years ago
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