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bekas [8.4K]
3 years ago
7

Identify the terms, like terms, corfficients, and constants in each expression. 2x+3y+7

Mathematics
1 answer:
harina [27]3 years ago
3 0

Answer:

terms: 2x, 3y

like terms: n/a

coefficients: 2, 3

constants: 7

Step-by-step explanation:

terms: matching variables

coefficients: numbers in front of the variable

constants: number that does not change

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Find the length of midsegment YZ in trapezoid ABCD when A(-5,-6) B(-6,-2) C(-4,0) and D(3,2)
Luda [366]

Answer:

Option C

Step-by-step explanation:

Since, Y and Z are the midpoints of sides AB and CD of the given trapezoid.

Segment YZ will the midsegment of trapezoid ABCD.

By the theorem of midsegment,

m(YZ) = \frac{1}{2}(AD+BC)

By using expression for the length of a segment between two points,

Length of a segment = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Distance between two points A(-5, -6) and D(3, 2),

AD = \sqrt{(3+5)^2+(2+6)^2}

AD = \sqrt{64+64}

AD = \sqrt{128}

AD = 8\sqrt{2}

Distance between B(-6, -2) and C(-4, 0)

BC = \sqrt{(-6+4)^2+(-2-0)^2}

BC = \sqrt{8}

BC = 2\sqrt{2}

Therefore, m(YZ) = \frac{1}{2}(8\sqrt{2}+2\sqrt{2})

                             = \frac{1}{2} (10\sqrt{2})

                             = 5\sqrt{2}

Option C will be the answer.

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3 years ago
Solve for x. 2x + 16 = 3(x - 9)
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First, distribute the 3 to the parentheses.
2x + 16 = 3x - 27
Add 27 to the left.
2x + 43 = 3x
Subtract 2x to the right.
43 = x
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Step-by-step explanation:

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