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Vika [28.1K]
3 years ago
15

Does the interest rate increase at a constant rate?

Mathematics
2 answers:
emmasim [6.3K]3 years ago
7 0
No.

From 6 mo to 12 mo, it increases 0.6%.
From 12 mo to 18 mo, it increases 0.1%. The change over a 6 mo period gets smaller as the period gets longer or the rate gets higher.
TiliK225 [7]3 years ago
6 0
Neverminding for a second that the rate is in percents.

it seems what's being asked is, "is the change from a month to the next, constant", as in an arithmetic sequence, well, check the picture below, those coordinates do not give us a straight line, and therefore, we don't have an arithmetic sequence, and therefore, we don't have a "common difference".

and since we don't have a common difference, the rate is not constant.

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A shirt that is normally 19.95 is on sale for 20% off what is the sale price​
MAVERICK [17]

Answer:

$15.96

Step-by-step explanation:

Sales price = $19.95

Discount = 20%

Amount paid = $19.95 - ($19.95*20%) = $19.95 - $3.99 = $15.96

6 0
3 years ago
Read 2 more answers
Eva has £6.05 in her moneybox.
PIT_PIT [208]

Answer:

11 of 20p, 22 of 10p and 33 of 5p

Step-by-step explanation:

Eva has 20p, 10p and 5p coins, total of £6.05 = 605p

Let 20p=x, 10p=y, 5p=z

<u>Then</u>:

  • 20x + 10y + 5z = 605
  • y : x = 2 : 1 ⇒ x= y/2
  • y : z = 2 : 3 ⇒ z= 3y/2

<u>Rewriting the first equation considering next two:</u>

  • 10y + 10y + 7.5y = 605
  • 27.5y = 605
  • y= 605/27.5
  • y= 22
  • x= y/2 = 22/2 = 11
  • z = 3y/2 = 3*11 = 33

<u>Answer:</u> 11 of 20p coins, 22 of 10p coins and 33 of 5p coins

3 0
3 years ago
2. Evaluate the expression for q = 2 6​
GenaCL600 [577]

Answer:

12

Step-by-step explanation:

This may not be intirely correct because you said q = 2 6. I think that means 2 times 6.

Anyways

2 x 6 = 12

⇒ q = 12

5 0
3 years ago
Graph triangle RST with vertices R(3, 7), S(-5, -2), and T(3, -5) and its image after a reflection over x = -3.​
kirill115 [55]

Given:

The vertices of a triangle are R(3, 7), S(-5, -2), and T(3, -5).

To find:

The vertices of the triangle after a reflection over x = -3 and plot the triangle and its image on the graph.

Solution:

If a figure reflected across the line x=a, then

(x,y)\to (-(x-a)+a,y)

(x,y)\to (-x+a+a,y)

(x,y)\to (2a-x,y)

The triangle after a reflection over x = -3. So, the rule of reflection is

(x,y)\to (2(-3)-x,y)

(x,y)\to (-6-x,y)

The vertices of triangle after reflection are

R(3,7)\to R'(-6-3,7)

R(3,7)\to R'(-9,7)

Similarly,

S(-5,-2)\to S'(-6-(-5),-2)

S(-5,-2)\to S'(-6+5,-2)

S(-5,-2)\to S'(-1,-2)

And,

T(3,-5)\to T'(-6-3,-5)

T(3,-5)\to T'(-9,-5)

Therefore, the vertices of triangle after reflection over x=-3 are R'(-9,7), S'(-1,-2) and T'(-3,-5).

3 0
3 years ago
I need help please????
sergeinik [125]

Answer:

the answer is 19

Step-by-step explanation:

30< on the graph is shown on the scores line, the kids that had scores 30< were totaled to 10+9  which equals 19

4 0
3 years ago
Read 2 more answers
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