All categories

3 years ago

Round these numbers to 1

Mathematics

1 answer:

s344n2d4d5 [400]3 years ago

3 0

Answer:

A) 6.4

B) 13.2

C)26.5

D)154.3

E)282.4

F)0.3

You might be interested in

Which boxes have a volume of 120 cubic feet? (4 points)

sergiy2304 [10]

Answer:

A,D

Step-by-step explanation:

5x4x6=120

10x3x4=120

5 0

3 years ago

Read 2 more answers

The sum of two numbers is 115. One number is 5 more than the other. Determine the two numbers.

prisoha [69]

Answer:

Number 1 is 55

Number 2 is 60 :)

Step-by-step explanation:

(115 - 5)/2

110/2

Number 1 is 55

Number 2 is 60 :)

60 + 55

110 + 5

115 :)

Have an amazing day!!

Please rate and mark brainliest!!

8 0

2 years ago

Read 2 more answers

Consider this Venn diagram of the prime factors of 210 and 330. Which is the least common multiple of these two numbers?

Mrrafil [7]

The least common multiple of these two numbers is 2310. Hope this helps

5 0

4 years ago

Susie has planned a trip to a city 60 miles away. She wishes to have an average speed of 60 miles/hour for the trip. Due to a tr

Nutka1998 [239]

Answer:

90 mi/h

Step-by-step explanation:

Given,

For first 30 miles, her speed is 30 miles per hour,

Let x be her speed in miles per hour for another 30 miles,

Since, here the distance are equal in each interval,

So, the average speed of the entire journey

$=\frac{\text{Average speed for first 30 miles + Average speed for another 30 miles}}{2}$

$=\frac{30+x}{2}$

According to the question,

$\frac{30+x}{2}=60$

$30+x=120$

$\implies x = 90$

Hence, she needs to go 90 miles per hour for remaining 30 miles.

7 0

4 years ago

A/ab-bsquare + b/ab-asquare?

lord [1]

Answer:

$\dfrac{(a+b)}{ab}$

Step-by-step explanation:

The given expression is :

$\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}$

It can be solved as follows :

$\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}=\dfrac{a}{b(a-b)}+\dfrac{b}{a(b-a)}\\\\=\dfrac{a}{b(a-b)}+\dfrac{b}{-a(-b+a)}\\\\=\dfrac{1}{a-b}(\dfrac{a}{b}-\dfrac{b}{a})\\\\=\dfrac{a^2-b^2}{ab(a-b)}\\\\=\dfrac{(a-b)(a+b)}{ab(a-b)}\\\\=\dfrac{(a+b)}{ab}$

So, the solution of the given expression is equal to $\dfrac{(a+b)}{ab}$ .

7 0

3 years ago