Answer:
Step-by-step explanation:
<u>Add up as fractions:</u>
- 1/2 + 2/5 = Common denominator is 2*5 = 10
- 5/10 + 4/10 =
- 9/10
Option D
<span>go tot he website of
</span>
https://www.algebra.com/algebra/homework/Problems-with-consecutive-odd-even-integers/Problems-with-c...
It will help you understand the problem and give you the answer.
600,000 i believe . just do 6000x10= 60,000 then times that by 10
For (2), start with the base case. When n = 2, we have
(n + 1)! = (2 + 1)! = 3! = 6
2ⁿ = 2² = 4
6 > 4, so the case of n = 2 is true.
Now assume the inequality holds for n = k, so that
(k + 1)! > 2ᵏ
Under this hypothesis, we want to show the inequality holds for n = k + 1. By definition of factorial, we have
((k + 1) + 1)! = (k + 2)! = (k + 2) (k + 1)!
Then by our hypothesis,
(k + 2) (k + 1)! > (k + 2) 2ᵏ = k•2ᵏ + 2ᵏ⁺¹
and k•2ᵏ ≥ 2•2² = 8, so
k•2ᵏ + 2ᵏ⁺¹ ≥ 8 + 2ᵏ⁺¹ > 2ᵏ⁺¹
which proves the claim.
Unfortunately, I can't help you with (3). Sorry!