Hey there!!
Given equation :
... x² + 5x - 6
... x² + 6x - x - 6
... x ( x + 6 ) - 1 ( x + 6 )
... ( x - 1 ) ( x + 6 ) is the answer.
Hope my answer helps!!
Remember, you can do anything to an equation as long as you do it to both sides
we hates fractions
times both sides by 3
(we could have added 1/3b to both sides but I'm lazy)
4b+6=12-b
add b to both sides
5b+6=12
minus 6 both sides
5b=6
divide both sides by 5
Do you understand what I did here?
The answer is: [C]: " ∡<em>C</em> ≅ ∡<em>X</em> ; ∡<em>D</em> ≅ ∡<em>Y</em> ; ∡<em>A</em> ≅ ∡<em>Z</em> " .
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