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Marina CMI [18]
3 years ago
8

Find x3 - 2y2 - 3x3 + z4 if x = 3, y = 5, and z = -3.

Mathematics
2 answers:
zloy xaker [14]3 years ago
6 0
So will be 27 -50 - 81 +81 = - 23

hope this will help you 
Goshia [24]3 years ago
3 0
Substitute the given values for x, y, and z in the expression,
                         x³ - 2y² - 3x³ + z^4
                         3³ - 2(5)² - 3(3³) + (-3)^4
The numerical value for the expression is -23. This is the third among the choices. 
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Please help <br><br> A 35<br> B 62<br> C 25<br> D 40
zvonat [6]
Answer: 35

Step-by-step-explanation:
There are 20 numbers. So, it would be 7 divided by 20. Which is 0.35. And 0.35 multiply by 100 is 35.
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46 is the sum of 9 and Hector's savings. Use the variable h to represent Hector's savings
AURORKA [14]
H+9=46
it would be a decimal
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4 years ago
Find the slope of the line passions through the points(-6,3) and (-6,-1)
VLD [36.1K]

Answer:

The slope of this line would be undefined.

Step-by-step explanation:

In order to find the slope of any line, use the slope formula.

m(slope) = (y2 - y1)/(x2 - x1)

m = (3 - -1)/(-6 - -6)

m = (3 + 1)/(-6 + 6)

m = 4/0

Since we cannot divide by 0, then we know the slope is undefined.

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4 years ago
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A histogram will show how quickly over time how many donations were made.

5 0
4 years ago
Write an equation of the perpendicular bisector of the segment with the endpoints (8,10) and ( -4,2).
ale4655 [162]

Answer:

The required equation is:

y = -\frac{3}{2}x+9

Step-by-step explanation:

To find the equation of a line, the slope and y-intercept is required.

The slope can be found by finding the slope of given line segment. A the perpendicular bisector of a line is perpendicular to the given line, the product of their slopes will be -1 and it will pass through the mid-point of given line segment.

Given points are:

(x_1,y_1) = (8,10)\\(x_2,y_2) = (-4,2)

We will find the slope of given line segment first

m = \frac{y_2-y_1}{x_2-x_1}\\= \frac{2-10}{-4-8}\\=\frac{-8}{-12}\\=\frac{2}{3}

Let m_1 be the slope of perpendicular bisector then,

m.m_1 = -1\\\frac{2}{3}.m_1 = -1\\m_1 = \frac{-3}{2}

Now the mid-point

(x,y) = (\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2})\\= (\frac{8-4}{2} , \frac{10+2}{2})\\=(\frac{4}{2}, \frac{12}{2})\\=(2,6)

We have to find equation of a line with slope -3/2 passing through (2,6)

The equation of line in slope-intercept form is given by:

y = m_1x+b

Putting the value of slope

y= -\frac{3}{2}x+b

Putting the point (2,6) to find the y-intercept

6 = -\frac{3}{2}(2)+b\\6 = -3+b\\b = 6+3 =9

The equation is:

y = -\frac{3}{2}x+9

7 0
3 years ago
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