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Ulleksa [173]
3 years ago
5

A quantity with an initial value of 1700 grows exponentially at a rate such that the quantity doubles every 5 years. What is the

value of the quantity after 81 months, to the nearest hundredth?
Mathematics
1 answer:
Nikolay [14]3 years ago
4 0

Answer: 4333.51

Step-by-step explanation:

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What does the word partial mean.
levacccp [35]
Not completely or not the full thing

hope this helps ! and hope you pass !
5 0
3 years ago
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Jeffrey has an aquarium in the shape of a rectangular prism. He is going to place a layer of sand over the base for his iguana.
nikitadnepr [17]

Answer:

Length = 6x^2 - 2x + 3

Step-by-step explanation:

Given

Area = 42x^3 - 14x^2 + 21x

Width = 7x

Required

Determine the length of the aquarium

The area of a rectangular base is calculated as:

Area = Length * Width

Substitute values for Area and Width

42x^3 - 14x^2 + 21x = Length * 7x

Make Length the subject

Length = \frac{42x^3 - 14x^2 + 21x}{7x}

Factorize the numerator

Length = \frac{7x(6x^2 - 2x + 3)}{7x}

Length = 6x^2 - 2x + 3

8 0
3 years ago
Let X equal the number of typos on a printed page with a mean of 4 typos per page.
timama [110]

Answer:

a) There is a 98.17% probability that a randomly selected page has at least one typo on it.

b) There is a 9.16% probability that a randomly selected page has at most one typo on it.

Step-by-step explanation:

Since we only have the mean, we can solve this problem by a Poisson distribution.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

In this problem, we have that \mu = 4

(a) What is the probability that a randomly selected page has at least one typo on it?

Thats is P(X \geq 1). Either a number is greater or equal than 1, or it is lesser. The sum of the probabilities must be decimal 1. So:

P(X < 1) + P(X \geq 1) = 1

P(X \geq 1) = 1 - P(X < 1)

In which

P(X < 1) = P(X = 0).

So

P(X = 0) = \frac{e^{-4}*4^{0}}{(0)!} = 0.0183

P(X \geq 1) = 1 - P(X < 1) = 1 - 0.0183 = 0.9817

There is a 98.17% probability that a randomly selected page has at least one typo on it.

(b) What is the probability that a randomly selected page has at most one typo on it?

This is P = P(X = 0) + P(X = 1). So:

P(X = 0) = \frac{e^{-4}*4^{0}}{(0)!} = 0.0183

P(X = 1) = \frac{e^{-4}*4^{1}}{(1)!} = 0.0733

P = P(X = 0) + P(X = 1) = 0.0183 + 0.0733 = 0.0916

There is a 9.16% probability that a randomly selected page has at most one typo on it.

3 0
3 years ago
Choose the slope-intercept form of 3x + 2y = 5
wlad13 [49]

Answer:

y = -3/2x + 5/2

Step-by-step explanation:

slope intercept form is y = mx + b

so we have to solve the equation for y

2y = 5 - 3x

y = 5/2 -3/2x

or

y = -3/2x + 5/2

8 0
3 years ago
Write the equation of the line that passes through the points (2 , -1) and has a slope of - 3​
svetlana [45]

Answer:

y=-3x+5

Step-by-step explanation:

y=mx+b

m=slope or gradient (=-3)

y=-3x+b  

Add your points

(2, -1)

-1=(-3 x 2)+b

-1= -6+b

-1+6=b

b=5

y=-3x+5

5 0
3 years ago
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