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devlian [24]
4 years ago
6

What is the result when you run the following program? print("2 + 7') print(3 + 1)

Computers and Technology
2 answers:
alukav5142 [94]4 years ago
7 0

Answer:

2 + 7

3 + 1

Explanation:

The program prints whatever you tell it to print

dlinn [17]4 years ago
4 0
The program tells you what to print
You might be interested in
Information systems security is the collection of activities that protect the information system and the data stored in it.
ivann1987 [24]

Answer:

The answer is A. True.

Explanation:

Information systems security,refers to all the methods involved with assuring information integrity as well as keeping it confidential, and available.

It can also be defined as -

The detection and provisoon of solutions to security breaches.

Access controls, which prevents unauthorized system access.

Protection of information either in transit or in a storage area.

3 0
3 years ago
Write a Java program in jGRASP that creates a 2D integer array of 5 rows and 20 columns, fills it with increasing integer values
Alex73 [517]

Answer:

As per the question we need to make 5 rowa and 2o columns, in this we have total element 100 so range should be 0 to 99, but we are suggested to keep range 0 to 59, so i have kept the elementns in the range, but if it was a typo in the question for range you do not need to reset the k with zero.

Explanation:

//create a new class  TestArray

public class TestArray {

//define main method

public static void main(String[] args) {

 //declare a 2D array of given size i.e. 5 rows and 20 columns

 int arr[][] = new int[5][20];

 //declare an integer variable k and initialize it with zero, this will used to initialize the array from 0 to 99

 int k = 0;

 //for loop for rows

 for (int i = 0; i < 5; i++) {

  //for loop for columns

  for (int j = 0; j < 20; j++) {

   //initialize arr with the current value of k

   arr[i][j] = k;

   //once k is 59 set it zero again as we are not going beyond 59

   if(k == 59)

    k = 0;

   //increment value of k with 1

   k++;

  }

 }

 //print the element from the array one by one

 //for loop for rows

 for (int i = 0; i < 5; i++) {

  //for loop for columns

  for (int j = 0; j < 20; j++) {

   //print the current element of array and an space with it

   System.out.print(arr[i][j]+" ");

  }

  // move the cursor to new line

  System.out.println();

 }

}

}

7 0
4 years ago
Consider a sequence of 1's and 1's with the property that the sum of any prefix of the sequence is never negative For example th
MrMuchimi

Answer:

Check the explanation

Explanation:

Answer: Solution: Algorithm:

Step 1: Start.

Step 2: Create a stack Step

3: Push an initial stack variable, it will represent that, stack is empty.

Step 4: Get input

             If +1 then push "+1"

             Else if -1 then pop

Step 5: Repeat until all input finish or Stop if empty stack variable popped. Step 6: Stop.

It is a pushdown automata problem.

It can be also represented as:

X =1+1* —1* 1No(+1)>= No(-1)}

4 0
3 years ago
Write a class called DisArray with methods to convert a 1-dimensional array to a 2-dimensional array. The methods' name should b
meriva
<h2>Answer:</h2>

=======================================================

//Class header definition

public class DisArray {

   //First method with int array as parameter

   public static void convert2D(int[] oneD) {

       //1. First calculate the number of columns

       //a. get the length of the one dimensional array

       int arraylength = oneD.length;

       //b. find the square root of the length and typecast it into a float

       float squareroot = (float) Math.sqrt(arraylength);

       //c. round off the result and save in a variable called row

       int row = Math.round(squareroot);

       //2. Secondly, calculate the number of columns

       //a. if the square of the number of rows is greater than or equal to the

       //length of  the one dimensional array,

       //then to minimize padding, the number of

       //columns  is the same as the number of rows.

       //b. otherwise, the number of columns in one more than the

       // number of rows

       int col = ((row * row) >= arraylength) ? row : row + 1;

       //3. Create a 2D int array with the number of rows and cols

       int [ ][ ] twoD = new int [row][col];

       //4. Place the elements in the one dimensional array into

       //the two dimensional array.

       //a. First create a variable counter to control the cycle through the one

       // dimensional array.

       int counter = 0;

       //b. Create two for loops to loop through the rows and columns of the

       // two  dimensional array.

       for (int i = 0; i < row; i++) {

           for (int j = 0; j < col; j++) {

               //if counter is less then the length of the one dimensional array,

               //then  copy the element at that position into the two dimensional

               //array.  And also increment counter by one.

               if (counter < oneD.length) {

                   twoD[i][j] = oneD[counter];

                   counter++;

              }

              //Otherwise, just pad the array with zeros

               else {

                   twoD[i][j] = 0;

               }

           }

       }

       //You might want to create another pair of loop to print the elements

       //in the  populated two dimensional array as follows

       for (int i = 0; i < twoD.length; i++) {

           for (int j = 0; j < twoD[i].length; j++) {

               System.out.print(twoD[i][j] + " ");

           }

           System.out.println("");

       }

   }     //End of first method

   //Second method with String array as parameter

   public static void convert2D(String[] oneD) {

       //1. First calculate the number of columns

       //a. get the length of the one dimensional array

       int arraylength = oneD.length;

       //b. find the square root of the length and typecast it into a float

       float squareroot = (float) Math.sqrt(arraylength);

       //c. round off the result and save in a variable called row

       int row = Math.round(squareroot);

       //2. Secondly, calculate the number of columns

       //a. if the square of the number of rows is greater than or equal to the length of  

       //the one dimensional array, then to minimize padding, the number of

       //columns  is the same as the number of rows.

       //b. otherwise, the number of columns in one more than the

       //number of rows.

       int col = (row * row >= arraylength) ? row : row + 1;

       //3. Create a 2D String array with the number of rows and cols

       String[][] twoD = new String[row][col];

       //4. Place the elements in the one dimensional array into the two

       // dimensional array.

       //a. First create a variable counter to control the cycle through the one

       // dimensional array.

       int counter = 0;

       //b. Create two for loops to loop through the rows and columns of the

       //two  dimensional array.

       for (int i = 0; i < row; i++) {

           for (int j = 0; j < col; j++) {

               //if counter is less then the length of the one dimensional array,

               //then  copy the element at that position into the two dimensional

               //array.  And also increment counter by one.

               if (counter < oneD.length) {

                   twoD[i][j] = oneD[counter];

                   counter++;

               }

               //Otherwise, just pad the array with null values

               else {

                   twoD[i][j] = null;

               }

           }

       }

       //You might want to create another pair of loop to print the elements  

       //in the populated two dimensional array as follows:

       for (int i = 0; i < twoD.length; i++) {

           for (int j = 0; j < twoD[i].length; j++) {

               System.out.print(twoD[i][j] + " ");

           }

           System.out.println("");

       }

   }    // End of the second method

   //Create the main method

   public static void main(String[] args) {

       //1. Create an arbitrary one dimensional int array

       int[] x = {23, 3, 4, 3, 2, 4, 3, 3, 5, 6, 5, 3, 5, 5, 6, 3};

       //2. Create an arbitrary two dimensional String array

       String[] names = {"abc", "john", "dow", "doe", "xyz"};

       

       //Call the respective methods

       convert2D(x);

       System.out.println("");

       convert2D(names);

   }         // End of the main method

}            // End of class definition

=========================================================

==========================================================

<h2>Sample Output</h2>

23 3 4 3  

2 4 3 3  

5 6 5 3  

5 5 6 3  

abc john dow  

doe xyz null

==========================================================

<h2>Explanation:</h2>

The above code has been written in Java and it contains comments explaining each line of the code. Please go through the comments. The actual executable lines of code are written in bold-face to distinguish them from the comments.

8 0
3 years ago
In a particular field, there are trees in a l single row from left to right. Each tree has a value V You cut trees from left to
Sedbober [7]

Answer:

i dont know help me

Explanation:

4 0
3 years ago
Read 2 more answers
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