If f(x) = 3x + 1 and f^-1 = x-1/3 , then f^-1(7) = A . 22 B . 2 C . -2

[30 POINTS] Please help!!!

Len [333]

Answer:

Part 1) $y=1.5x+5$

Part 2) $y=-(2/3)x-(11/3)$

Part 3) $y=0.25x+2.75$

Part 4) $y=-2x+5$

Part 5) $y=0.5x-1$

Part 6) The graph in the attached figure

Step-by-step explanation:

Part 1) we have

$m=3/2=1.5$

$point(-2,2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-2=1.5(x+2)$

$y=1.5x+3+2$

$y=1.5x+5$

Part 2) we know that

If two lines are perpendicular

then

the product of their slopes is equal to minus one

so

$m1*m2=-1$

the slope of the line 1 is equal to

$m1=1.5$

Find the slope m2

$1.5*m2=-1$

$m2=-2/3$

Find the equation of the line 2

we have

$m2=-2/3$

$point(-7,1)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-1=(-2/3)(x+7)$

$y=-(2/3)x-(14/3)+1$

$y=-(2/3)x-(11/3)$

Part 3) we have

$m=1/4=0.25$

$point(1,3)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-3=0.25(x-1)$

$y=0.25x-0.25+3$

$y=0.25x+2.75$

Part 4) we have

$m=-2$

$b=5$ -----> y-intercept

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

substitute the values

$y=-2x+5$

Part 5) we have that

The slope of the line 4 is equal to $-2$

so

the slope of the line perpendicular to the line 4 is equal to

$-2*m=-1\\m=(1/2)=0.5$

therefore

in this problem we have

$m=0.5$

$point(-2,-2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y+2=0.5(x+2)$

$y=0.5x+1-2$

$y=0.5x-1$

Part 6)

using a graphing tool

see the attached figure

3 0

2 years ago

Identify the ordered pair that represents the vector from A(-8,-1) to B(-5,3) and the magnitude of vector AB.

wel

In order to find the vector that points from A to B we need to subtract each component of A from the corresponding component of B, according to the formula: v(a→b)=(b1−a1,b2−a2) In this case we have : v(a→b)=(−5−(−8),3−(−1)) v(a→b)=(3,4)

To find the magnitude we use the formula: ||v|= √(v1^2)+(v1^2)

So:
||v|= √(32)+(42) ||v|= √9+16 ||v|= √25 ||v|= 5

8 0

3 years ago

Find the equation of the straight line which is parallel to 2x + 3y = 11 and such that the sum of the intercepts on axes is 15.

Burka [1]

Answer: 2x+3y=18

Step-by-step explanation: Any line parallel to 2x+3y+11=0 is the form 2x+3y =k this can also be written as x/(k/2)+y/k/3 =1 this is the line whose sum of the intercepts is 15, then k/2 +k/3 = 15 after solving we get that indeedk= 18.

5 0

2 years ago

Write .11111 as a fraction in simplest form.

luda_lava [24]

Answer:

11111/100000

Step-by-step explanation:

Good luck

3 0

2 years ago

Which of the images above represent a proof of the Pythagorean Theorem? Explain your choice, and then explain how the figure pro

puteri [66]

From the second figure it can be seen that 25 + 144 = 169

This implies that 5^2 + 12^2 = 13^2

This is a right triangle with legs of 5 and 12 and hypothenus of 13.

7 0

2 years ago

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