A fertilizer company manufactures 10-pound bags of fertilizer with a standard deviation of 0.24 pounds per bag. The bag weights
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Answer:
For this case we know this:
We can find the standard error like this:
So then our random variable can be described as:
Let's suppose that the question on this case is find the probability that the population proportion would be higher than 0.4:
We can use the z score given by:
And using this we got this:
And we can find this probability using the Ti 84 on this way:
2nd> VARS> DISTR > normalcdf
And the code that we need to use for this case would be:
1-normalcdf(-1000, 3.04; 0;1)
Or equivalently we can use:
1-normalcdf(-1000, 0.4; 0.2;0.0658)
Step-by-step explanation:
We need to check if we can use the normal approximation:
We assume independence on each event and a random sampling method so we can conclude that we can use the normal approximation and then ,the population proportion have the following distribution :
For this case we know this:
We can find the standard error like this:
So then our random variable can be described as:
Let's suppose that the question on this case is find the probability that the population proportion would be higher than 0.4:
We can use the z score given by:
And using this we got this:
And we can find this probability using the Ti 84 on this way:
2nd> VARS> DISTR > normalcdf
And the code that we need to use for this case would be:
1-normalcdf(-1000, 3.04; 0;1)
Or equivalently we can use:
1-normalcdf(-1000, 0.4; 0.2;0.0658)