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3 years ago

Helppp!!! Louis donated money to what he believed to be a reputable charity. He later

Mathematics

1 answer:

ira [324]3 years ago

6 0

Answer:

Report the incident to the federal trade commission

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On a long-distance biking trip, annike started biking at 7 a.M., and her average speed was 11 miles per hour. Celia started at 8

gladu [14]

Answer:

3.67 hours

Step-by-step explanation:

Speed is the ratio of distance to time, it is given by the formula:

Speed = Distance / time

For annike her average speed was 11 miles per hour and she started at 7 am.

At 8 am (time = 1 hr i.e 7 am to 8 am) the distance she would have covered is given as:

11 miles/hr = distance / 1 hr

Distance = 11 miles per hr × 1 hr = 11 miles

After 8 am, the distance traveled at time t is:

11 = distance/t

distance = 11t

Total distance = 11t + 11

For Celia she started at 8 am at 14 miles per hour, at time t, the distance traveled is:

14 = distance/t

Distance = 14t

Given that both bikers traveled the same distance, hence:

14t = 11t + 11

3t = 11

t = 11/3

t = 3.67 hours

5 0

3 years ago

3/4 : 1/2 how do I make these fractions in this ration into decimals

Svet_ta [14]

0.75 : 0.5

3 • 25 = 75,, 4 • 25 = 100,, making it 0.75

1 • 50 = 50,, 2 • 50 = 100,, making it 0.5

4 0

4 years ago

7.4=n-2.6 could you plz solve this or give me some good sites that could solve it for me oh and plz show the steps to thanks

lisov135 [29]

Please try to follow this closely.
Ready ? OK, here goes:

<em> Add 2.6 to each side of the equation.</em>

6 0

3 years ago

Read 2 more answers

Witch is a equation is equivalent to 3[x+3(4x - 5)]

hodyreva [135]

3( x+ 3(4x-5))

3x + 9(4x-5)

3x + 36x - 45

39x - 45 is equivalent to 3( x+ 3(4x-5))

8 0

2 years ago

10 POINTS

Svetradugi [14.3K]

Answer:

C, F, D

Step-by-step explanation:

For each side of each triangle, think of the side as the hypotenuse of a right triangle. Then use the Pythagorean theorem to find the length of the hypotenuse, which is the side of the triangle.

Left problem:

From point C to point A, go 2 left and 7 up.

$AC = \sqrt{2^2 + 7^2} = 7.3$

From point A to point B, go 5 right and 1 down.

$AB = \sqrt{5^2 + 1^2} = 5.1$

From point B to point C, go 6 down and 3 left.

$BC = \sqrt{6^2 + 3^2} = 6.7$

Perimeter = 7.3 + 5.1 + 6.7 = 19.1

Do the same for the other triangles.

Middle problem:

From point F to point D, go 2 left and 7 up.

$FD = \sqrt{2^2 + 7^2} = 7.3$

From point D to point E, go 7 right and 2 down.

$DE = \sqrt{7^2 + 2^2} = 7.3$

From point E to point F, go 5 down and 5 left.

$EF = \sqrt{5^2 + 5^2} = 7.1$

Perimeter = 7.3 + 7.3 + 7.1 = 21.7

Right problem:

From point L to point J, go 7 left and 1 up.

$LJ = \sqrt{7^2 + 1^2} = 7.1$

From point J to point K, go 4 up and 5 right.

$JK = \sqrt{4^2 + 5^2} = 6.4$

From point K to point L, go 2 right and 5 down.

$KL = \sqrt{2^2 + 5^2} = 5.4$

Perimeter = 7.1 + 6.4 + 5.4 = 18.9

4 0

3 years ago