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Dimas [21]
3 years ago
5

Order 7\8,0.98, 8/9 from least to greatest

Mathematics
1 answer:
Aleks04 [339]3 years ago
4 0

.875 .88 .98

7/8, 9/9, .98 is your answer from least to greatest!

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How many positive 3-digit numbers are divisible by 11?
enyata [817]

Answer:

81

Step-by-step explanation:

If a number is divisible by 11, then you can make those numbers by multiplying 11 by any number. Like 33 is divisible by 11 because 3×11 is 33.

Of course, 33 is too small, we are looking for 3-digit numbers...

see image.

4 0
1 year ago
When determining if you have a perfect square trinomial, what must the first and third term be?
cricket20 [7]

The expansion of a perfect square is

(a+b)^2 = a^2+2ab+b^2

In words, the square of a sum of two terms is the sum of the squares of the two terms (a^2 and b^2), plus twice the product of the two terms (2ab)

So, when determining if you have a perfect square trinomial, you should have two perfect squares. Note that they don't have to be the first and third term, since you can rearrange terms as you prefer.

8 0
3 years ago
A square field has a perimeter if 3.6km what is the length of one side in metres​
spayn [35]

Answer:

A square field has a perimeter if 3.6km what is the length of one side in metres

Step-by-step explanation:

A square field has a perimeter if 3.6km what is the length of one side in metres

4 0
2 years ago
Read 2 more answers
WILL GIVE BRAINLIEST graph -8=2x-y using the x and y intercepts (show your work pls)
Ahat [919]

Answer:

-8=2x-y get this into y=mx+b form to find the y-intercept

-y=-2x-8

y=2x+8

the y-intercept is 8 so it passes through (0,8)

to find the x-intercept, set y to equal zero

0=2x+8

-8=2x

x=-4

the x-intercept is -4 so it passes through (-4,0)

the slope is 2 based on the slope-intercept form

7 0
3 years ago
FURTHER MATHEMATICS Use determinants to solve the systems of equation:
maw [93]

Answer:

Step-by-step explanation:

\left\{\begin{array}{ccc}2x+1y+2z&=&13\\1x+1y-2z&=&8\\1x+2y+1z&=&11\\\end{array}\right.\\\\\\\Delta=\left| \begin{array}{ccc}2&1&2\\1&1&-2\\1&2&1\end{array}\right| =2*\left| \begin{array}{ccc}1&\frac{1}{2}&1\\1&1&-2\\1&2&1\end{array}\right| =2*\left| \begin{array}{ccc}1&\frac{1}{2}&1\\0&\frac{1}{2}&-3\\0&1&3\end{array}\right| =2*(\frac{3}{2}+3)=9\\\\

\Delta_1=\left| \begin{array}{ccc}13&1&2\\8&1&-2\\11&2&1\end{array}\right| =2*\left| \begin{array}{ccc}13&1&2\\8&1&-2\\\frac{11}{2}& 1&\frac{1}{2}\end{array}\right| =2*\left| \begin{array}{ccc}13&1&2\\-5&0&-4\\\frac{-5}{2}& 0&\frac{5}{2}\end{array}\right| \\\\=2*(-1)*(\frac{-25}{2}-\frac{20}{2}) =45\\

\Delta_2=\left| \begin{array}{ccc}2&13&2\\1&8&-2\\1&11&1\end{array}\right| \\\\\\=\left| \begin{array}{ccc}3&21&0\\3&30&0\\1&11&1\end{array}\right| \\\\\\=1*(90-63) =27\\

\Delta_3=\left| \begin{array}{ccc}2&1&13\\1&1&8\\1&2&11\end{array}\right| \\\\\\=\left| \begin{array}{ccc}0&-1&-3\\0&-1&-3\\1&2&11\end{array}\right| \\\\\\=0\\

\left\{\begin{array}{ccc}x=\dfrac{\Delta_1}{\Delta}=\dfrac{45}{9}=5\\\\y=\dfrac{\Delta_2}{\Delta}=\dfrac{27}{9}=3\\\\z=\dfrac{\Delta_3}{\Delta}=\dfrac{0}{9}=0\\\end{array}\right.

8 0
3 years ago
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