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Nonamiya [84]
3 years ago
5

WILL GIVE BRAINLIEST!!!!!! Look at the picture of a scaffold used to support construction workers. The height of the scaffold ca

n be changed by adjusting two slanting rods, one of which, labeled PR, is shown: Part A: What is the approximate length of rod PR? Round your answer to the nearest hundredth. Explain how you found your answer, stating the theorem you used. Show all your work. Part B: The length of rod PR is adjusted to 17 feet. If width PQ remains the same, what is the approximate new height QR of the scaffold? Round your answer to the nearest hundredth. Show all your work.

Mathematics
1 answer:
maksim [4K]3 years ago
4 0

Answer:

A). PR = 16.13 ft

B). QR = 9.64 ft

Step-by-step explanation:

Part (A).

From the figure attached,

ΔPQR is a right triangle,

m(PQ) = 14 ft

m(QR) = 8 ft

By applying Pythagoras theorem,

Hypotenuse² = (Leg 1)² + (Leg 2)²

(PR)² = (PQ)² + (QR)²

(PR)² = (14)² + (8)²

PR = √260

     = 16.125

     ≈ 16.13 ft

Part (B).

If PR = 17 feet

and PQ = 14 feet

By applying Pythagoras theorem in ΔPQR,

PR² = PQ² + QR²

(17)² = (14)² + (QR)²

(QR)² = 289 - 196

QR = √93

     = 9.644

     ≈ 9.64 ft

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A coach is assessing the correlation between the number of hours spent practicing and the average number of points scored in a g
cricket20 [7]

Answer:

a) r=\frac{9(396)-(18)(153)}{\sqrt{[9(51) -(18)^2][9(3141) -(153)^2]}}=1  

We have a perfect linear relationship between the two variables

b) m=\frac{90}{15}=6  

Nowe we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{18}{9}=2  

\bar y= \frac{\sum y_i}{n}=\frac{153}{9}=17  

And we can find the intercept using this:  

b=\bar y -m \bar x=17-(6*2)=5  

So the line would be given by:  

y=6 x +5  

c) For this case the slope indicates that for each increase of the number of hours in 1 unit we have an expected increase in the score about 6 units.

And the intercept 5 represent the minimum score expected for any game

Step-by-step explanation:

We have the following data:

Number of hours spent practicing (x) 0 0.5 1 1.5 2 2.5 3 3.5 4

Score in the game (y) 5 8 11 14 17 20 23 26 29

Part a

The correlation coefficient is given:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

For our case we have this:

n=9 \sum x = 18, \sum y = 153, \sum xy = 396, \sum x^2 =51, \sum y^2 =3141  

r=\frac{9(396)-(18)(153)}{\sqrt{[9(51) -(18)^2][9(3141) -(153)^2]}}=1  

We have a perfect linear relationship between the two variables

Part b

m=\frac{S_{xy}}{S_{xx}}  

Where:  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}  

With these we can find the sums:  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=51-\frac{18^2}{9}=15  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=396-\frac{18*153}{9}=90  

And the slope would be:  

m=\frac{90}{15}=6  

Nowe we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{18}{9}=2  

\bar y= \frac{\sum y_i}{n}=\frac{153}{9}=17  

And we can find the intercept using this:  

b=\bar y -m \bar x=17-(6*2)=5  

So the line would be given by:  

y=6 x +5  

Part c

For this case the slope indicates that for each increase of the number of hours in 1 unit we have an expected increase in the score about 6 units.

And the intercept 5 represent the minimum score expected for any game

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3 years ago
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Vlada [557]

Answer:

a

Step-by-step explanation:

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Answer:

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let's say it takes both of them working together say "t" hours, so in 1 hour Bob has done (1/14) of the work whilst James has done (1/18) of the work, the whole work being t/t or 1 whole, so for just one hour that'd 1/t done by both Bob and James.

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3 years ago
PLS HELP<br><br> Find the value of x and y.
riadik2000 [5.3K]

Answer:

x= 27.71281 = 16√3

y= 13.85641 = 8√3

Step-by-step explanation:

hope it helps :)

3 0
2 years ago
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