Answer:
Step-by-step explanation:
(0,1) (1, -3)
(-3 - 1)/(1 - 0)= -4/1= -4
y - 1 = -4(x - 0)
y - 1 = -4x + 0
y = -4x + 1: equation
slope: -4
y int: 1 or (0, 1)
35/100 but simplified its 7/20
I guess you're asking about the probability density for the random variable where are independent and identically distributed uniformly on the interval (0, 15). The PDF of e.g. is
It's easy to see that the support of is the same interval, (0, 15), since , and
• at most, if and , or vice versa, then
• at least, if , then
Compute the CDF of :
This probability corresponds to the integral of the joint density of over a subset of a square with side length 15 (see attached). Since are independent, their joint density is
The easiest way to compute this probability is by using the complementary region. The triangular corners are much easier to parameterize.
In the second integral, substitute and , so that
which is the same as the first integral. This tells us the joint density is symmetric over the two triangular regions.
Then the CDF is
We recover the PDF by differentiating with respect to .
For what values of b is f(x) = b^x an increasing function?
<span><span>
A.Any real number
</span><span>B.b > 0
</span><span>C.b > 1
</span><span>D.<span>0< b <1
</span></span></span>