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3 years ago

Given the equation 2Square root of x minus 5 = 2, solve for x and identify if it is an extraneous solution.

Mathematics

2 answers:

sashaice [31]3 years ago

6 0

Answer:

x=196

Step-by-step explanation:

In order to solve this you just have to clear X fro the equation and solve:

$2\sqrt{x} - 5=2\\ 2\sqrt{x}=2+5\\\sqrt{x}=7*2\\x=14^2\\x=196$ Once you´ve calculated this you have the solution for the equation, that is x.

It is not an extraneous solution.

Aleks [24]3 years ago

4 0

For what values of b is f(x) = b^x an increasing function?

A.Any real number
B.b > 0
C.b > 1
D.0

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Two positive numbers have a difference of 8 and a product of 33. What are these numbers?

valina [46]

Answer:

3 and 11

Step-by-step explanation:

3 times 11 is 33

11 - 3 is 8

4 0

3 years ago

Danna's age is 6 years less than 8 times Tessa's age. If Tessa's age is x years, which expression best shows Danna's age?

Marat540 [252]

6 - 8x is the correct answer

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3 years ago

Read 2 more answers

A man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream. Fin

pochemuha

The speed of the current is 40.34 mph approximately.

SOLUTION:

Given, a man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream.

We have to find the speed of the current if the speed of the boat is 11 mph in still water. Now, let the speed of river be a mph. Then, speed of boat in upstream will be a-11 mph and speed in downstream will be a+11 mph.

And, we know that, $\text{ distance } =\text{ speed }\times \text{ time }$

$\begin{array}{l}{\text { So, for upstream } \rightarrow 40=(a-11) \times \text { time taken } \rightarrow \text { time taken }=\frac{40}{a-11}} \\\\ {\text { And for downstream } \rightarrow 70=(a+11) \times \text { time taken } \rightarrow \text { time taken }=\frac{70}{a+11}}\end{array}$

We are given that, time taken for both are same. So $\frac{40}{a-11}=\frac{70}{a+11}$

$\begin{array}{l}{\rightarrow 40(a+11)=70(a-11)} \\\\ {\rightarrow 40 a+440=70 a-770} \\\\ {\rightarrow 70 a-40 a=770+440} \\\\ {\rightarrow 30 a=1210} \\\\ {\rightarrow a=40.33}\end{array}$

8 0

3 years ago

Help me please ASAP!!

Tcecarenko [31]

Hello there k12 user. - i am in k12 too :)

cough.

use mathpapa look it up it should give your anwser i cant copy and paste it, but its there
just put in the numbers

6 0

3 years ago

The difference of two numbers is equal to 0.6. Their quotient is also 0.6. What are the numbers? There are 4

Makovka662 [10]

Let the two numbers be represented by x and y. The problem statement gives rise to two sets of equations.
x - y = 0.6
y/x = 0.6 . . . . . . . assuming x is the larger of the two numbers
or
x/y = 0.6 . . . . . . . assuming y has the larger magnitude

The solution of the first pair of equations is
(x, y) = (1.5, 0.9)

The solution of the first and last equations is
(x, y) = (-0.9, -1.5)

The pairs of numbers could be {0.9, 1.5} or {-1.5, -0.9}.

8 0

3 years ago