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den301095 [7]
3 years ago
7

Given the equation 2Square root of x minus 5 = 2, solve for x and identify if it is an extraneous solution.

Mathematics
2 answers:
sashaice [31]3 years ago
6 0

Answer:

x=196

Step-by-step explanation:

In order to solve this you just have to clear X fro the equation and solve:

2\sqrt{x} - 5=2\\ 2\sqrt{x}=2+5\\\sqrt{x}=7*2\\x=14^2\\x=196Once you´ve calculated this you have the solution for the equation, that is x.

It is not an extraneous solution.

Aleks [24]3 years ago
4 0

For what values of b is f(x) = b^x an increasing function? 
<span><span>
A.Any real number 
</span><span>B.b > 0 
</span><span>C.b > 1 
</span><span>D.<span>0< b <1

</span></span></span>
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Hello,
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===============

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