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mario62 [17]
3 years ago
9

The system of equations above is graphed below. Find the solution to the system.

Mathematics
1 answer:
Oksana_A [137]3 years ago
7 0

Option D: x=3,y=-2 is the solution to the system of equations.

Explanation:

Given that the equations are 4x+y=10 and 2x+y=4

We need to determine the solution of the system of equations.

The solution can be determined by solving the two equations.

Let us solve the system of equations using substitution method.

Consider the equation 4x+y=10 , the value of y is given by

y=10-4x

Substituting the value of y=10-4x in the equation 2x+y=4 , we get,

2x+(10-4x)=4

Simplifying, we get,

2x+10-4x=4

     -2x+10=4

             -2x=-6

                 x=3

Substituting the value of x=3 in 4x+y=10 , we get,

4(3)+y=10

  12+y=10

         y=-2

Thus, the solution to the system of equations is x=3,y=-2

Hence, Option D is the correct answer.

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Bo and Erica are yoga instructors. Between the two of them, they teach 48 yoga classes each week. If Erica teaches 12 fewer than
oee [108]
Answer:
Bo teaches 20 classes per week.
Erica teaches 28 classes per week.
Step-by-step explanation:
Let x= yoga classes taught by Bo
and y=yoga classes taught by Erica
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8 0
2 years ago
Please help me to solve the question. (chapter angle between two lines)​
dsp73

Answer:    \bold{x^2-\dfrac{181}{13}xy+12y^2=0}

<u>Step-by-step explanation:</u>

\tan \theta =\dfrac{y}{x}\quad \longrightarrow \theta=\tan ^{-1}\bigg(\dfrac{y}{x}\bigg)

\text{Given:}\quad \theta =\tan^{-1}\bigg(\dfrac{1}{13}\bigg)\quad \longrightarrow x=13,y=1

Insert x = 13 and y = 1:

x² + 2hxy + 12y² = 0

(13)² + 2(13)(1) + 12(1)² = 0

169 + 26h + 12 = 0

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                26h = -181

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\text{Insert:}\ h=-\dfrac{181}{26}

x^2 + 2\bigg(-\dfrac{181}{26}\bigg) xy + 12y^2 = 0

\bold{x^2 -\bigg(\dfrac{181}{13}\bigg) xy + 12y^2 = 0}

8 0
3 years ago
(a)
Marrrta [24]
B. (20 characters long)
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3 years ago
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