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3 years ago

Solve for a p^2+a^2/r =k

Mathematics

1 answer:

lys-0071 [83]3 years ago

5 0

I think it's D bc I looked it up in internet and it's what It gave me

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Pls help me on this rq

Anarel [89]

Answer:

second answer

Step-by-step explanation:

n is greater than -6 and less than 8 bc the number has to be inbetween -6 and 8, so those are the only ones thatmake snse

7 0

4 years ago

8. Which of the following equations represents

aalyn [17]

Answer:

d y=-5x-8

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Mila reads at a rate of 3 paragraphs per minute.

dusya [7]

no of minutes = x

no of paragraphs = y

ATQ

2x = y

if x = 1 if x = 2 if x = 3

2 (1) = y 2(2) = y 2(3) = y

2 = y 4 = y 6 = y

(x,y) = (1, 2) (x, y) = (2, 4) (x, y) = (3, 6)

8 0

3 years ago

Read 2 more answers

Find all of the zeros

noname [10]

Answer:

{-3, -1, 1}

Step-by-step explanation:

Zeros refer to x-intercepts. X-intercepts are x values when y = 0. You can tell where they are by looking at where the line passes the x-axis.

Therefore, {-3, -1, 1} are the zeros.

3 0

4 years ago

Y+1=2/5(x+3) in standard form?

Rzqust [24]

For this case we have that by definition, the equation of a line in the standard form is given by:

$ax + by = c$

According to the statement we have the following equation of the line:

$y + 1 = \frac {2} {5} (x + 3)$

We manipulate algebraically to write in the standard form. To do this we follow the steps below:

We apply distributive property on the right side of the equation: $y + 1 = \frac {2} {5} x + \frac {6} {5}$

We subtract $\frac {6} {5}$ on both sides of the equation:

$y + 1- \frac {6} {5} = \frac {2} {5} x\\y- \frac {1} {5} = \frac {2} {5} x$

We multiply by 5 on both sides of the equation:

$5y-1 = 2x$

We subtract 5y on both sides of the equation:

$2x-5y = -1$

Finally, the equation in its standard form is:

$2x-5y = -1$

Answer:

$2x-5y = -1$

6 0

4 years ago